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Y_Kistochka [10]
4 years ago
9

Find all solutions in the integers of the equation ||x−3|−5| = 10, where the bars indicate absolute value.

Mathematics
1 answer:
Helga [31]4 years ago
3 0

Answer:

x = 18 or x = -12.

Step-by-step explanation:

||x-3|-5| = 10 only if |x-3|-5 = 10 or |x-3|-5 = -10, i.e., if |x-3|=15 or |x-3|=-5; but |x-3| cannot be equal to -5, because |x-3| should be a non-negative value. Therefore, the first equation is true only if |x-3|=15. |x-3| = 15 only if x-3 = 15 or x-3 = -15, i.e., x = 18 or x = -12.  We can verify this in the following way: ||18-3|-5|=||15|-5|=|10|=10 and ||-12-3|-5|=||-15|-5|=|15-5|=|10|=10. This verify that our solution is correct.

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noah was asked to compute the product of two numbers. he misread the problem and entered the sum of the two numbers instead. luc
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The other number is 1.25 .

proved to us , the first number is 5 .

let the other number is 'x' .

therefore we are having ,

the product of these numbers = 5x

the sum of these numbers = 5 + x

Also , the product of these two numbers is equal to the sum of these two numbers

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