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Akimi4 [234]
2 years ago
15

The test scores for the exam in statistics class have a mean of 78 points and standard deviation of 9 points. A student is rando

mly selected. Assuming the scores are normally distributed find the probability that the score is more than 95. write statement!
Mathematics
1 answer:
frutty [35]2 years ago
3 0

Answer: the answer is 809

Step-by-step explanation:

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Solve x(−2) 2 =4(−2)
Simora [160]
Hi there,

X x (-2) x 2 = 4 x (-2)
- x = - 2

Hence, X = 2

Hope this helps :)
7 0
3 years ago
How do you write an equation for "a number decreased by negative 7 is the same thing as 48
just olya [345]
N-(-7)=48 I'm not sure though
3 0
3 years ago
Read 2 more answers
Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

4 0
3 years ago
What is the answer? Please tell me! I am in a hurry...
Nikitich [7]
I think it would be C
6 0
3 years ago
Read 2 more answers
1+4(6p-9) simplified
snow_lady [41]

Answer

24p+ (-31)

Step-by-step explanation:

  1. P.EM.D.A.S
  2. 4*6p=24p
  3. 4*-9=-36
  4. now it looks like: 1+4+24p+-36
  5. now for addition 1+4+24p+-36= 24p+ (-31)
5 0
3 years ago
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