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Shtirlitz [24]
3 years ago
5

Make y the subject of the formula

Mathematics
2 answers:
Rus_ich [418]3 years ago
6 0

Answer:

What do you mean by 'A ya X-W B y="a c y= x'-' Do you have a photo by any chance

stepladder [879]3 years ago
6 0
Waht is the meaning A ya X-W?
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I'm horrible at this please help:((((​
wel

Step-by-step explanation:

You can insert different values of x to find y

For example:

x = 4

Plug in x into the equation

y = -1/2(4) + 5

y = -2 + 5

y = 3

So your point will be (4, 3)

If you do 1 more like this, you can draw a line between them. Or you can use Desmos to graph the line.

Hope this helped you!!

8 0
3 years ago
What is standard form?
Katen [24]

Hey there! :)

When teachers ask you for the standard form in math, they are asking you to find the simplest form an equation with variables can be in.

Ax + By = C

Example : put y=2x -3 into standard form.

Subtract 2x from both sides.

-2x + y = -3 —> standard form.

Hope this helped! :)

7 0
3 years ago
Read 2 more answers
X − (y − y)= for x = 3 and y = 6
dusya [7]

Answer:

3

Step-by-step explanation:

x − (y − y)

3-(6-6)

3-0

3

3 0
3 years ago
Read 2 more answers
The mean time required to repair breakdowns of a certain copying machine is 93 minutes. The company which manufactures the machi
Sonja [21]

Answer:

t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349    

p_v =P(t_{(72)}  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=88.8 represent the sample mean

s=26.6 represent the sample standard deviation for the sample  

n=73 sample size  

\mu_o =93 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean i lower than 93 min, the system of hypothesis would be:  

Null hypothesis:\mu \geq 93  

Alternative hypothesis:\mu < 93  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=73-1=72  

Since is a one side test the p value would be:  

p_v =P(t_{(72)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.  

5 0
3 years ago
In Whitehorse, the high temperature for the day was 7°C, and in Yellowknife the high for the same day was -8°C. What was the dif
Lesechka [4]
The difference between the two cities are that each temp is different their 14c away because their is a minus on the eight
6 0
3 years ago
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