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Anestetic [448]
3 years ago
5

5 boys and 6 girls attend a birthday party and play pin the tail on the donkey. If a girl wins first and second place and a boy

wins third place, How many different arrangements of first, second, and third are there? =
Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
5 0

Answer:

75 Arrangements

Step-by-step explanation:

Girl can secure 1st & 3rd, boy can secure 2nd position in : 6 x 5 x 5 = 150 ways ; As :

  • 1st position holder can be chosen in 6 ways (among 6 girls)
  • 2nd position holder can be chosen in 5 ways (among 5 boys)
  • 3rd position holder can be chosen in ( among 5 remaining girls)

The arrangement of first, second & third  :

It is same : If Girl G1 gets first rank & Girl G2 gets third rank, is same as ; Girl G1 gets third rank & Girl G2 gets first rank. So, two are considered the same group. Hence, number of arrangements are 150 / 2 = 75  arrangements.

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How many rectangular prisms 8 inches long, 5 inches wide, and 2 inches high can fit into another rectangular prism that measures
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Answer:

20

Step-by-step explanation:

Volume of rectangular prism = length × width × height

Length = 8 inches

Width = 5 inches

Height = 2 inches

Volume of rectanglular prism = length × width × height

= 8 inches * 5 inches * 2 inches

= 80 inches ³

Dimensions of another rectangular prism:

Length = 16 inches

Width = 10 inches

Height = 10 inches

Volume of rectangular prism B = length × width × height

= 16 inches * 10 inches * 10 inches

= 1,600 inches ³

Number of prism A that fits into prism B = Volume of prism B ÷ volume of prism A

= 1,600 inches ³ ÷ 80 inches ³

= 20

Number of prism A that fits into prism B = 20

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