Answer:
228
Step-by-step explanation:
We are adding 3 each time so general rule is
Tn= 3n + 3
Therefore
T= 3(75)+3
= 228
2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
Answer:
Wish i can help but i don't understand that
Step-by-step explanation:
13*18
x*y =234
x+y=31
we know the 2 # have to be double digits and both between 10-20
find 2 values that * to a number that ends in 4. Those are the ones value
1*4 11 and 14
2*2 12 and 12
3*8 13 and 18
only 13 and 18 add up to 31 and multiply to 234
Answer:
6=n
Step-by-step explanation:
16 - 2n = -8 + 4(n -3)
16-2n=-8+4n-12
+2n +2n
____________-
16=-8+6n-12
16=-20+6n
+20 +20
___________
36=6n
÷6 ÷6
_________
6=n
Hope this helps :D
