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3 years ago

Help please!!! My last questions.

Mathematics

1 answer:

olga2289 [7]3 years ago

4 0

Answer:

mean: 8.4 median: 7 mode: 6

Step-by-step explanation:

mean add all the numbers up and divide them by how many of them there are.

median put them in order smallest to largest then find the middle number

mode the number that comes up in the line the most

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I need to know how to work it out someone plz help me out due tommorow

DiKsa [7]

Multiply 75 by 1.0675 to find the total amount of tax plus 100 percent of the original fee im pretty sure and for the seocnd one multiply 450 by 1.45

5 0

3 years ago

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.

$h^-^1\ o\ h$

$\frac{(3x+4)-4}{3}\\\\=\frac{3x+4-4}{3}\\\\=\frac{3x}{3}\\\\=x$

Now substitute (-3) in place of (x),

$=-3$

8 0

3 years ago

2³+2²+2÷2²+2+1=2 prove that this relation is true for any natural numbers

UkoKoshka [18]

So, this question is basically asking us "If we had an x instead of a 2, would this be true?" We can try and see what we get:

$\frac{x^3+x^2+x}{x^2+x+1}=x$

So, if we want to show this we have to change the numerator or denominator in such a way that we can cancel some common factors. Notice that $x^3+x^2+x=x(x^2+x+1)$