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3 years ago

True or false: Every kite is a rhombus, but not every rhombus is a kite.

1 answer:

7 0

This is false. Kites can be shaped in many different ways so not all kites are rhombuses. Also, even the kites that look like rhombuses may not be rhombuses. Most kites have 2 pairs of sides with the same length. But, in order to be a rhombus all the sides have to be the same length but not all sides are the same length on a typical kite.

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98. What is the sum of the first 27 terms in the arithmetic series 25 +19+13 + ...?

jeka57 [31]

Answer:

sum of the first 27 terms = -1431

Step-by-step explanation:

<h3>arithmetic series sum of the first n terms formula:</h3>

$s_{n} = \frac{n}{2} (2a + (n - 1)d)$

n = 27 terms

first term, a = 25

common difference, d = 19 - 25 = -6

substitute the values into the formula

$s_{27} = \frac{27}{2} (2(25) + (27 - 1)( - 6))$

$s_{27} = 13.5(50 + 26( - 6))$

$s_{27} = 13.5(50 - 156)$

$s_{27} = 13.5( - 106)$

$s_{27} = - 1431$

4 0

2 years ago

Add 3 feet 6 in add 3 feet 6 in + 8 ft 2 in + 4in + 2ft 5in what does that add up to

Troyanec [42]

Answer:

173 inches

Step-by-step explanation:

i don't entirely understand the question but i think you're trying to add 3 feet 6 inches + 8 feet 2 inches + 4 inches + 2 feet 5 inches?

(3 feet 6 inches) + (8 feet 2 inches) + (4 inches) + (2 feet 5 inches)

i've added these parentheses in order to make it easier to see the grouped measurements. this isn't necessary but i'm just doing it to hopefully aid my explanation since there's so many terms in the expression!

start by converting everything to inches just to make the addition as well as showing your work easier. all you have to do is multiply the amount of feet by 12 because there are 12 inches in a foot! :)

(3 feet 6 inches) + (8 feet 2 inches) + (4 inches) + (2 feet 5 inches)

for your first measurement, 3 feet 6 inches, convert 3 feet to inches by multiplying the amount of feet, 3, by 12.

3(12) = 36 (therefore 3 feet is equal to 36 inches!)

and add the remaining 6 inches.

36 + 6 = 42 (therefore 3 feet 6 inches is equal to 42 inches!)

(3 feet 6 inches) + (8 feet 2 inches) + (4 inches) + (2 feet 5 inches)

for your second measurement, 8 feet 2 inches, convert 8 feet to inches by multiplying the amount of feet, 8, by 12.

8(12) = 96 (therefore 8 feet is equal to 96 inches!)

and add the remaining 2 inches.

96 + 2 = 98 (therefore 8 feet 2 inches is equal to 98 inches!)

(3 feet 6 inches) + (8 feet 2 inches) + (4 inches) + (2 feet 5 inches)

nothing needs to be done to this quantity since it's already in inches.

(3 feet 6 inches) + (8 feet 2 inches) + (4 inches) + (2 feet 5 inches)

for your fourth measurement, 2 feet 5 inches, convert 2 feet to inches by multiplying the amount of feet, 2, by 12.

2(12) = 24 (therefore 2 feet is equal to 24 inches!)

and add the remaining 5 inches.

24 + 5 = 29 (therefore 2 feet 5 inches is equal to 29 inches!)

now, here is the expression with everything in inches.

42 inches + 98 inches + 4 inches + 29 inches aka 42 + 98 + 4 + 29

now add everything up!

42 + 98 + 4 + 29 = 173 inches

your total is 173 inches! i hope this helps and i hope i explained it well enough. have a lovely day! <3

5 0

3 years ago

Jordan needs 5 pounds of chips for a party. The bags he is buying are 24 oz each. According to the number line, how many bags wi

strojnjashka [21]

Answer:

3.33 but he cant buy 3 and 1/3 of a bag of chips so 4

Step-by-step explanation:

4 0

2 years ago

Steve can complete the 100m dash in 10 seconds by Paul can run it in 12 seconds how does Steve's time compared to Paul's

Gwar [14]

Paul can run 10m per 1 second

Steve can run 8.333m per 1 second

4 0

3 years ago

Read 2 more answers

The Municipal Transit Authority wants to know if, on weekdays, more passengers ride the northbound blue line train towards the c

Kitty [74]

Answer:

The 90% confidence interval $-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

The distribution test statistics is $t = -3.222$

The rejection region is p-value < $\alpha$

The decision rule is reject the null hypothesis

The conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

The p-value is $p-value =0.000951$

Step-by-step explanation:

From the question we are told that

The first sample size $n_1 = 30$

The first sample mean is $\= x _1 = 323$

The first standard deviation is $s_1 = 41$

The second sample size is $n_2 = 45$

The second sample mean is $\=x_2 = 356$

The second standard deviation is $s_2 = 45$

given that the confidence level is 90% then the level of significance is mathematically represented as

$\alpha = (100 -90)\%$

$\alpha = 0.10$

Generally the critical value of $\frac{\alpha }{2}$ obtained from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the pooled variance is mathematically represented as

$s^2 = \frac{(n_1 - 1)s_1^2 + (n_2 -1)s_2^2 }{n_1 + n_2 -2}$

$s^2 = \frac{(30 -1)(41^2) + (45-1)45^2}{30+45 -2}$

$s^2 = 1888.34$

Generally the standard error is mathematically represented as

$SE = \sqrt{\frac{s^2}{n_1} + \frac{s^2}{n_2} }$

=> $SE = \sqrt{\frac{1888.34}{30} + \frac{1888.34}{45} }$

=> $SE = 10.24$

Generally the margin of error is mathematically evaluated as

$E = Z_{\frac{\alpha }{2} } * SE$

$E = 1.645* 10.24$

$E = 16.85$

Generally the 90% confidence interval is mathematically represented as

$\=x_1 -\=x_2 -E < \mu_1 -\mu_2 < \=x_1 -\=x_2 +E$

$323 -356 -16.84$

$-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \=x_2 }{SE}$

=> $t = \frac{323-356}{10.24}$

=> $t = -3.222$

Generally the degree of freedom is mathematically represented as

$df = n_1+n_2 -2$

$df = 30 + 45 -2$

$df = 73$

The p-value is obtained from the student t distribution table at degree of freedom of 73 at 0.05 level of significance

The value is $p-value =0.000951$

Here the level of significance is $\alpha = 5\% = 0.05$

Given that the p-value < $\alpha$ then we reject the null hypothesis

Then the conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

5 0

3 years ago