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KiRa [710]
3 years ago
14

Sean wants to make a frame for a painting. The painting is square and has area 196 square inches. The framing material costs ​$1

.05 per inch. How much will he ​spend? You may assume that the framing material buys will be the exact amount needs.
Mathematics
1 answer:
prisoha [69]3 years ago
7 0

Answer:

$58.80

Step-by-step explanation:

Area = Length * Width              square frame length & width will be the same

√196 = 14 inches                      

  196 = 14 * 14

   196 = 196

14 inches * 4 sides = 56 inches total needed for frame

Cost:

  56 inches * $1.05 = $58.80

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What is the solution to the equation 9-3x = 7?
emmasim [6.3K]

Answer:

x = \frac{2}{3}

Step-by-step explanation:

Given

9 - 3x = 7 ( subtract 9 from both sides )

- 3x = - 2 (divide both sides by - 3 )

x = \frac{-2}{-3} = \frac{2}{3}

4 0
3 years ago
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2 years ago
A patrolman spends 25% every day completing paperwork. The patrolman’s shift each day is 8 hours. How much of his time does he s
fredd [130]
Assuming the man works 8 hours straight without breaks:

25% is the same as 1/4 of something.

So, we just have to figure out what 1/4 (one quarter) of 8 equals.

You can think of it as a pizza cut into 8 slices. One slice is equivalent to one hour for the patrolman.

If we take away 1/2 (half) of the pizza, we have 4 slices, right? Since we start with 8 slices, half of that equals 4 slices. In other words, 50% (half) of the pizza = 4 slices.

Now, 25% (one quarter) of the pizza will equal half of what is left:

If we know that 50%=4 slices (or 4 hours), then 25% must be 2 slices (or 2 hours).

That's it! 25% of 8 hours = 2 hours.

***So, the patrolman spends 2 hours each day completing paperwork.***

Lets check our work:
We know 8 hours (or 8 slices)= 100%
(We know this because
8 slices = 1 whole pizza, or 100% of a pizza. Similarly,
8 hours = 1 whole shift or 100% of the man's shift ).

So

25% + 25% + 25% + 25% = 100%

If 100% of the mans shift = 8 hours:

2+2+2+2 = 8

It checks out!


Hope this helps!



4 0
3 years ago
Out of 80 workers surveyed at a company, 11 walk to work A. What is the experimental probability that a randomly selected worker
s344n2d4d5 [400]

Answer:

Below.

Step-by-step explanation:

A. Required probability = 11/80.

B. 3700 * 11/80 = 508.75 so the predicted number would be 509.

8 0
2 years ago
Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^
Gemiola [76]

Answer:

\rm \displaystyle y' =   2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x}

Step-by-step explanation:

we would like to figure out the differential coefficient of e^{2x}(1+\ln(x))

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

\displaystyle y =  {e}^{2x}  \cdot (1 +   \ln(x) )

to do so distribute:

\displaystyle y =  {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x}

take derivative in both sides which yields:

\displaystyle y' =  \frac{d}{dx} ( {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x} )

by sum derivation rule we acquire:

\rm \displaystyle y' =  \frac{d}{dx}  {e}^{2x}  +  \frac{d}{dx}   \ln(x)  \cdot  {e}^{2x}

Part-A: differentiating $e^{2x}$

\displaystyle \frac{d}{dx}  {e}^{2x}

the rule of composite function derivation is given by:

\rm\displaystyle  \frac{d}{dx} f(g(x)) =  \frac{d}{dg} f(g(x)) \times  \frac{d}{dx} g(x)

so let g(x) [2x] be u and transform it:

\displaystyle \frac{d}{du}  {e}^{u}  \cdot \frac{d}{dx} 2x

differentiate:

\displaystyle   {e}^{u}  \cdot 2

substitute back:

\displaystyle    \boxed{2{e}^{2x}  }

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

\displaystyle  \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)

let

  • f(x) \implies   \ln(x)
  • g(x) \implies    {e}^{2x}

substitute

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =  \frac{d}{dx}( \ln(x) ) {e}^{2x}  +  \ln(x) \frac{d}{dx}  {e}^{2x}

differentiate:

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =   \boxed{\frac{1}{x} {e}^{2x}  +  2\ln(x)  {e}^{2x} }

Final part:

substitute what we got:

\rm \displaystyle y' =   \boxed{2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x} }

and we're done!

6 0
3 years ago
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