Answer: yes they are
Step-by-step explanation:
If two pairs of corresponding angles in a pair of triangles are congruent, then the triangles are similar. We know this because if two angle pairs are the same, then the third pair must also be equal.
We need to compute the diagonal of yhe square.
d²=7²+7²=49×2cm²
d=7×sqrt(2)=7×1.41=9.87cm.
The diagonal we just computed is the diameter of the circle that contains the square.
Since d=9.87 < 11, then indeed, the square fits inside the circle, without touching it.
Answer:
0.13 ft/min
Step-by-step explanation:
We are given that

We have to find the increasing rate of change of height of pile when the pile is 12 ft high.
Let d be the diameter of pile
Height of pile=h
d=h
Radius of pile,r=
Volume of pile=

h=12 ft
Substitute the values



Answer:
17.6 m²
Step-by-step explanation:
Given the ratio of similar shapes = a : b, then
area of shapes = a ² : b²
Δ PTQ and Δ PRS are similar and so the ratio of corresponding sides are equal, that is
PT : PR = 6 : 9 = 2 : 3, thus
ratio of areas = 2² : 3² = 4 : 9
let the area of Δ PQT be x, then using proportion
=
( cross- multiply )
9x = 4(x + 22) ← distribute
9x = 4x + 88 ( subtract 4x from both sides )
5x = 88 ( divide both sides by 5 )
x = 17.6
Thus area of Δ PQT = 17.6 m²