The initial value of 100 that doubles over each interval.
without the answer choices, I can only describe it and give you an example of the graph.
I'm assuming the function is 100*(2)^x because if it is as listed it would be a quadratic function with a vertical stretch of 100.
Answer:
2x^2 = 6x - 5.
-x^2 - 10x = 34.
These have only complex roots/
Step-by-step explanation:
3x^2 - 5x = -8
3x^2 - 5x + 8 = 0
There are complex roots if the discriminant 9b^2 - 4ac) is negative.
Here the discriminant D = (-5)^2 - 4*-5*8 = 25 + 160
This is positive so the roots are real.
2x^2 = 6x - 5
2x^2 - 6x + 5 = 0
D = (-6)^2 - 4*2*5 = 36 - 40 = -4
So this has no real roots only complex ones.
12x = 9x^2 + 4
9x^2 - 12x + 4 = 0
D = (-12)^2 - 4*9 * 4 = 144 - 144 = 0.
- Real roots.
-x^2 - 10x = 34
x^2 + 10x + 34 = 0
D = (10)^2 - 4*1*34 = 100 - 136 = -36.
No real roots = only complex roots.
Answer:
$162.94
Step-by-step explanation:
Because 20% off of 192.15 = $162.94 and
$153.72 + (6.0%) $9.22 = $162.94
Answer:
x = 13
Step-by-step explanation:
6x + 14 + 4x - 8 + 2x + 18 = 180 {Angle sum property of tiangle}
6x + 4x + 2x + 14 - 8 +18 = 180 {Combine like terms}
12x + 24 = 180 {Subtract 18 from both sides}
12x = 180 - 24
12x = 156 {Divide both sides by 12}
x = 156/12
x = 13
