Answer:
5:1 (answer c)
Step-by-step explanation:
Number right: 10
Number wrong: 2
Total number: 10 + 2 = 12
Ratio of right answers to number of wrong answers:
10/2 or 10:2, or (after reduction) 5:1
Well, can I see the line please?
Answer: 
Step-by-step explanation:
Since the general quadratic equation is,

Here the given table is,
x 1 2 3 4 5 6 7
y 5.9 8.9 13.4 20.1 30.1 45.1 67.7
By the graphing calculator,
a = 1.87024 ≈ 1.87
b= -5.15833 ≈ -5.15
c = 10.5429 ≈ 10.54
By putting the values of a, b and c,
The required quadratic equation is,

⇒ First Option is correct.
To find these out you have to use the strategy of P (parenthesis) E (exponents) M (multiplication) D (division) A (addition) S (subtraction)
3 - 4 x 2 The first thing you need to do is do the multiplication part first, since subtraction is the last thing you need to do. You multiply 4 and 2 and get the answer of 8, then subtract 3 which is 5
5 x 3 - 4 The first thing you need to do is multiplication 5 x 3 which equals 15 and then do 15 - 4 = 11
15 ÷ (3 x 5) x 2 The first thing you do is you do the P (parenthesis) which is (3x5) which equals 15. Then you multiply 15 with 2 which is 30 and then divide 30 with 15 which is 2
5 + 3 x 2 ÷ 6 First you need to do the Multiplication which is 3 x 2 which equals 6, and then you do the division, which is 6 ÷ 6 which is 1. Then add 5 to the 1 which is 6.
<em>Your welcome and please give brainly :)</em>
Answer:

Step-by-step explanation:
As per the question,
let us consider f(x) = tan(x).
We know that <u>The Maclaurin series is given by:</u>

So, differentiate the given function 3 times in order to find f'(x), f''(x) and f'''(x).
Therefore,
f'(x) = sec²x
f''(x) = 2 × sec(x) × sec(x)tan(x)
= 2 × sec²(x) × tan(x)
f'''(x) = 2 × 2 sec²(x) tan(x) tan(x) + 2 sec²(x) × sec²(x)
= 4sec²(x) tan²(x) + 2sec⁴(x)
= 6 sec⁴x - 4 sec² x
We then substitute x with 0, and find the values
f(0) = tan 0 = 0
f'(0) = sec²0 = 1
f''(0) = 2 × sec²(0) × tan(0) = 0
f'''(0) = 6 sec⁴0- 4 sec² 0 = 2
By putting all the values in the Maclaurin series, we get



Therefore, the expansion of tan x at x = 0 is
.