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Gwar [14]
3 years ago
11

What are the angle measurements of 1,2,3,4, &5?

Mathematics
1 answer:
salantis [7]3 years ago
5 0
1 = 180 - (30+41) = 109
2 = 180 - 109 = 71
3 = 180 - (54 + 71) = 55
4 = 180 - (54+71) = 55
5 = 95 - 54 = 41

I *think* this is correct. However, I took geometry 3 years ago so I may have forgotten some rules
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Find the measure of <2.
iVinArrow [24]
Should be 30 as well
5 0
3 years ago
Read 2 more answers
How to solve log5 x/2 = 5? i got it to 2^5=x/2 but i have NO CLUE how to solve from there?
Lerok [7]
Well
log_a(b)=c translates to a^c=b
so
log5(x/2)=5 means 5^5=x/2, so 3125=x/2, so 6250=x

4 0
3 years ago
A toy manufacturer claims that the mean time that its top-selling toy captures children's attention is at least 45 minutes. Supp
riadik2000 [5.3K]

Answer:

H_0:\mu =45\\\\H_a:\mu\geq 45

Step-by-step explanation:

Since we have given that

A toy manufacturer claims that the mean time that its top-selling toy captures children's attention is at least 45 minutes.

Since we need to carry out a hypothesis test whether he can refute the claim.

We always take the alternate hypothesis such that it should satisfy the given statement.

And the null hypothesis can be equal to mean or other than that is given in alternate hypothesis.

So, hypothesis :

H_0:\mu =45\\\\H_a:\mu\geq 45

5 0
3 years ago
A help would be greatly appreciated! 
dalvyx [7]
The tree was approximately 40.8ft tall.

You use the equation, a^2+b^2=c^2.
12^2 + 39^2 = x^2, add the results of 12^2 and 39^2 to make 1665 = x^2. You can take the positive root of both sides, 3√185, and it equals 40.80441152, which is rounded to 40.8.
7 0
4 years ago
The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum
wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information:P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000, where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2

Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

Now, again differentiating

\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

At x = 64,  \displaystyle\frac{d^2(P(x))}{dx^2} < 0

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0
3 years ago
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