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MakcuM [25]
3 years ago
11

3 to the 3rd power plus 20 divided by 2 to the second power

Mathematics
1 answer:
otez555 [7]3 years ago
3 0

Answer:

32

Step-by-step explanation:

3 to the 3rd power is 27 and 2 to the 2nd power is 4 so,

27+20 divided by 4

and PEMDAS so exponents, divided then add. 20 divided by 4 is 5. So 27+5 is 32. Hope this helps!

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I camper attaches a rope from the top of her tent 4 feet above the ground to give it more support if the Rope is 8 ft long about
iVinArrow [24]

Answer:

b = 6.928

Step-by-step explanation:

Looks like a job for the Pythagorean Theorem.

a^2 + b^2 = c^2

4^2 + b^2 = 8^2

16 + b^2 = 64

b^2 = 48

b = 6.928

Hope it helps!!

6 0
3 years ago
Out of a box 200 apples 10 of them has gotten bad
Olenka [21]

Answer: 1/20 and 19/20

Step-by-step explanation:

7 0
3 years ago
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Simplify the expression below 6m^5+15m^2/3m^2
densk [106]

Answer:6m^5+5

Step-by-step explanation:

To simplify 6m^5+15m^2/3m^2

We get

6m^5+5

8 0
3 years ago
What are the fourth roots of 6+6√(3i) ?
Helen [10]

Answer:

Step-by-step explanation:

The genral form of a complex number in rectangular plane is expressed as z = x+iy

In polar coordinate, z =rcos ∅+irsin∅ where;

r is the modulus = √x²+y²

∅ is teh argument = arctan y/x

Given thr complex number z = 6+6√(3)i

r = √6²+(6√3)²

r = √36+108

r = √144

r = 12

∅ = arctan 6√3/6

∅ = arctan √3

∅ = 60°

In polar form, z = 12(cos60°+isin60°)

z = 12(cosπ/3+isinπ/3)

To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)

z^1/4  = 12^1/4(cosπ/12+isinπ/12)

When n = 1;

z1 =  12^1/4(cosπ/3+isinn/3)

z1 = 12^1/4cis(π/3)

when n = 2;

z2 = 12^1/4(cos2π/3+isin2π/3)

z2 = 12^1/4cis(2π/3)

when n = 3;

z2 = 12^1/4(cosπ+isinπ)

z2 = 12^1/4cis(π)

when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

8 0
3 years ago
The function y=ex is vertically stretched by a factor of 2, reflected across the x-axis, and then shifted down 3 units, find the
Anettt [7]

Answer:

y = - 2 e^{x} - 3

Step-by-step explanation:

We have to vertically stretch the function y = e^{x} by a factor of 2.

Then the function will become y = 2e^{x}.

Then it is reflected across the x-axis.

So, the new function will be y = - 2e^{x}.

Now, if the function is shifted down 3 units then the final function will become y = - 2 e^{x} - 3 (Answer)

6 0
3 years ago
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