The first equation must be multiplied by 18 and second equation must be multiplied by 8
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
--------- eqn 1
-------------- eqn 2
Multiply the second equation by 8 both sides to remove the fraction in the variable y
Multiply the first equation by 18 both sides to obtain the coefficient -3 in the variable y
Add eqn 3 and eqn 4
Thus the y-term is eliminated
Therefore, first equation must be multiplied by 18 and second equation must be multiplied by 8
Answer:
Step-by-step explanation:
1. (sq root of) a^2 if a>0 => √(a^2) = ±a
2. (sq root of) 36x^2 if a>0 => ±6x
The ball was initially thrown from a height of 5.5 feet and 5.5 is y intercept that it throm from 5.5 feet.
10 3/5 + 12 1/2 =
10 6/10 + 12 5/10 =
23 1/10 =
35 - 23 1/10 =
11 9/10 =
11 9/10 miles
Hope that helps
Answer:
- changing the order of the numbers we are multiplying, does not change the product
Step-by-step explanation:
7 x 8 x 11 x 2 = 11 x 7 x 2 x 8
1232 = 1232
Hope it helps!
