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2 years ago

if 22000 pots with 15 seeds each are used in a nursery, how many total seeds, in scientific notation?

Mathematics

1 answer:

kipiarov [429]2 years ago

7 0

Write the total number of seeds in scientific notation

Given:

Number of pots = 22,000

Number of seeds = 15

Total number of seeds = Number of pots × Number of seeds

= 22,000 × 15

= 330,000

Scientific notation is written in multiples of 10

Count the number of digits
Insert a decimal point between the first digit and other digits
count the number of digits after the first digits
multiply by 10 raise to the power of number of remaining digits after first digits

= 3.30000 × 10^5

Therefore,

the total number of seeds in

scientific notation is 3.30000 × 10^5

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2 years ago

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Lana71 [14]

Answer:

Confidence limit = [52.8%, 75.2%]

Step-by-step explanation:

$P=\frac{45}{70}= 0.64$

$(1-P)=1-0.64=0.36$

$n= 70$

$P$ ± $z$ $\sqrt{\frac{P(1-P)}{n} }$

where the value $z$ will be taken from the z-table for 95% confidence interval

1-0.95= 0.05/2= 0.025

0.95+0.025= 0.0975

From the z-table the value of $z$ corresponding to 0.0975 is 1.96

$0.64$ ± $1.96$ $\sqrt{\frac{0.64*0.36}{70} }$

$0.64$ ± $1.96$ $(0.057)$

$0.64$ ± $0.112$

$64%$ % ± $11.2$ %

so the confidence interval is

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$[52.8, 75.2]$

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2 years ago

A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a stand

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Answer:

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Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

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$\mu_G = 15$