Answer:
6/12, 8/12, and 9/12.
Step-by-step explanation:
Let's find the least common denominator:
First, the least common multiple of 2, 3, and 4 is 12.
12 is divisible by 2, 3, and 4.
<u>Next, multiply the denominators with the numerators:</u>
Products: 6/12, 8/12, and 9/12
Soz man i use the metric system
4-1/2x=10
-1/2x=6
3
so your answer would be B
hope that helps
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, ![[ab]_K](https://tex.z-dn.net/?f=%20%5Bab%5D_K%20)
is equal to ![[ba]_K](https://tex.z-dn.net/?f=%20%5Bba%5D_K%20)
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, ![[ab]_H = [ba]_H](https://tex.z-dn.net/?f=%20%5Bab%5D_H%20%3D%20%5Bba%5D_H%20)
. Since a and b were generic elements of H, then H/G is abelian.
