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3 years ago

Helpppppppppppppp pleaseeeee

Mathematics

1 answer:

S_A_V [24]3 years ago

5 0

I dont know if this is the right but i tried

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In Δ,∠=70°,∠=50° ∠ . <br> ℎ ∠.

AveGali [126]

Answer:

100°

Step-by-step explanation:

A triangle is a polygon shape with three sides. Triangles are of different types such as obtuse, scalene, equilateral, isosceles etc.

In triangle ABC:

70° + 50° + ∠C = 180° (sum of angles in a triangle)

120 + ∠C = 180

∠C = 180 - 120

∠C = 60°

Since ∠C is bisected into ∠ACD and ∠BCD, hence:

∠ACD = ∠BCD = ∠C / 2

∠ACD = ∠BCD = 60 / 2

∠ACD = ∠BCD = 30°

In triangle ACD:

∠A + ∠ACD + ∠ADC = 180° (sum of angles in a triangle)

50 + 30 + ∠ADC = 180

∠ADC + 80 = 180

∠ADC = 100°

6 0

3 years ago

Point S is on line segment RT. Given RT=4x, ST = 5x-10, and RS = 6 determine the numerical length of ST.

Art [367]

Answer:

ST=10

Step-by-step explanation:

8 0

3 years ago

PLEASE HELP!!!<br> HSJSHGXDBSJHCBDSHDCB PLEASEE

KatRina [158]

Answer:

the answer is 30

............................

7 0

3 years ago

Read 2 more answers

What is the slope of the line that passes through the points (7, -4) and (7, 0)? Write your answer in the simplest form.

olga55 [171]

Answer:

The slop is undefined

i.e. $m=\infty$

Step-by-step explanation:

Considering the slope formula

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

As the points are (7, -4) and (7, 0)

Here:

(x₁, y₁) = (7, -4)

(x₂, y₂) = (7, 0)

$\mathrm{When\:}y_1\ne \:y_2\mathrm{\:and\:}\:x_1=x_2\mathrm{\:the\:slope\:is\:}\infty$

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$=\frac{\left(0-\left(-4\right)\right)}{\left(7-7\right)}$

$=\frac{0-\left(-4\right)}{0}$

$=\infty$

Therefore, the slop is undefined i.e. $m=\infty$

5 0

3 years ago

Solve the following system of linear equations: 3x1+6x2+6x3 = -9 -2x1–3x2-3x3 = 3 If the system has infinitely many solutions, y

choli [55]

Answer:

The set of solutions is $\{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number} \}$

Step-by-step explanation:

The augmented matrix of the system is $\left[\begin{array}{ccccc}3&6&6&-9\\-2&-3&-3&3\end{array}\right]$ .

We will use rows operations for find the echelon form of the matrix.

In row 2 we subtract $\frac{2}{3}$ from row 1. (R2- 2/3R1) and we obtain the matrix $\left[\begin{array}{cccc}3&6&6&-9\\0&1&1&-7\end{array}\right]$
We multiply the row 1 by $\frac{1}{3}$ .

Now we solve for the unknown variables:

$x_2+x_3=-7$ , $x_2=-7-x_3$
$x_1+2x_2+2x_3=-2$ , $x_1+2(-7-x_3)+2x_3=-2$ then $x_1=12$

The system has a free variable, the the system has infinite solutions and the set of solutions is $\{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number} \}$

6 0

3 years ago