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exis [7]
3 years ago
13

Which side lengths form a right triangle?

Mathematics
2 answers:
horrorfan [7]3 years ago
8 0
The answer is B. Because 8 , 3, 17 add up to the length of a triangle
Amanda [17]3 years ago
6 0

<u>Answer:</u>

<h2>B. √8, 3 and √17 form a right triangle</h2>

<u>Explanation:</u>

√8², 3² and √17² satisfy a²+b²=c²

√8²+3² = √17²

8+9=17

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a roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decora
Arada [10]

Answer:

The mass of each passenger is 550 kg.

The mass of front decoration is 200 Kg.

Step-by-step explanation:

Given : A roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decoration and only 4 passenger cars, it has a mass of 2400 kg.

To find : What is the mass of the decoration and of each passenger car?

Solution :

Let the mass of each passenger is x.

Let the mass of front decoration is y.

  • When the number of passenger = 6

Mass of 6 passengers and front decoration = 3500 kg.

The equation form is 6x+y=3500 ..........[1]

  • When the number of passengers = 4

Mass of 4 passengers and front decoration = 2400 kg.

The equation form is 4x+y=2400  ........[2]

Solving equation [1] and [2]

Subtract equation [2] from [1],

6x+y-4x-y=3500-2400

2x=1100

x=550

Put value in [1],

6(550)+y=3500

3300+y=3500

y=200

Therefore, The mass of each passenger is 550 kg.

The mass of front decoration is 200 Kg.

8 0
4 years ago
Solve for x<br> 14x = 5(2x – 4) – 12
ehidna [41]
The answer is
X = - 8
3 0
3 years ago
Read 2 more answers
Please help !!!!thank you .
vekshin1

Answer:

414

Step-by-step explanation:

12 times 7, 12 times 15, 7 times 15

4 0
3 years ago
What is the arc length of a circle (in meters) with a radius of 2 meters that has an arc angle of 90
Irina18 [472]

Answer:

Step-by-step explanation:

L=®/360°2πr

L=90/360×2×3.14×2m

L=3.14m

6 0
4 years ago
Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x = t7 + 1, y = t8
Jet001 [13]
I must assume that you meant t=1 (not t=?1).  If t=1, here's what we'd do:

1.  Find the x and y values corresponding to t=1.  They are:
      x=(1)^7+1=2     and    y=(1)^8+1=2.  (Please note:  write t^8 instead of t8,                and write t^7 instead of t7.)
2.  The slope of the tangent line to the graph is
                          dy/dt            8t^7+1
          dy/dx = ----------   = ---------------- with 1 substituted for t
                         dx/dt              7t^6
  
      Thus, dy/dx (at t=1) = 9/7

3.  Now we have both a point (2,2) on the graph and the slope of the tangent line to the curve at that point:  9/7

4.  The tangent line to the curve at (2,2) is  found by using the point-slope formula:

y-y1 = m(x-x1)

which comes out to y-2 = 9/7(x-2), or 7y-14 = 9(x-2).  You could, if you wished, simplify this result further (e. g., by solving for y in terms of x).
8 0
3 years ago
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