Answer:
40.15$
Step-by-step explanation:
subtract 20 from 60, you get 40. then add the 0.15 back. bam! 40.15$. hope this helped!! ^___^
Correct answers in reasoning and statements together.
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Hope this helps!!
Option C:
The coefficient of
is 40.
Solution:
Given expression:

Using binomial theorem:

Here 
Substitute in the binomial formula, we get

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.


Let us solve the term one by one.






Substitute these into the above expansion.

The coefficient of
is 40.
Option C is the correct answer.
Answer:

Step-by-step explanation:
We are given the equations
to search for a value of
that yields an equivalent statement.
.
There's no following. You need to post a picture or complete the question.