(-a^3b^2*-a^-2b^-3)^-2/2a^2b^-3
= a^4b^9/2a^8b^4
=b^5/2a^4
so your answer is b^5/2a^4
A.23/6
b.23/8
c.26/5
d.64/9
Answer:
Step-by-step explanation:
Let number of large pizzas be l and number of small be s.
<u>Then we have equations:</u>
- l + s = 100
- 16l + 11s = 1550
<u>From the first equation, we get l = 100 - s and substitute in the second equation:</u>
- 16(100 - s) + 11s = 1550
- 1600 - 16s + 11s = 1550
- 5s = 1600 - 1550
- 5s = 50
- s = 10
Number of small pizzas is 10
All others did not satisfy the inequality simultaneously except #4 and #6
For #4:
2 < 5(1) + 2 i.e. 2 < 7 (true)
2 >= 1/2(1) + 1 i.e. 2 >= 3/2 (true)
For #6
2 < 5(2) + 2 i.e. 2 < 12 (true)
2 >= 1/2(2) + 1 i.e. 2 >= 2
Did it the longer way but i hope it helps you out.... Answer: 2/3
