Need help now!! 30 points F(0) = ?

Identify where the student went wrong 2(x+5) = 29 2x + 5 = 29 2x = 24 x=14

lord [1]

Answer:

2x+5=29

Step-by-step explanation:

2(x+5)=29

x+5=29/2

x=14.5-5

x=9.5

8 0

3 years ago

The very busy Freshman class is selling tickets for an upcoming field hockey game. The class sells 20 more student tickets than

mixer [17]

Answer:

60 student tickets and 40 adult tickets were sold

Step-by-step explanation:

Let s represent student tickets and a adult tickets, then the system of equations can be written as

s - a = 20 →(1)

2s + 4a = 280 → (2)

Multiply (1) by 4 and add to (2) to eliminate a

4s - 4a = 80 → (3)

Add (2) and (3) term by term

6s = 360 ( divide both sides by 6 )

s = 60

Substitute s = 60 into (1)

60 - a = 20 ( subtract 60 from both sides )

- a = - 40 ( multiply both sides by - 1 )

a = 40

Thus

60 student and 40 adult tickets were sold.

7 0

3 years ago

Chucky grabbed 11 1111 items in the grocery store that each had a different price and had a mean cost of about $ 4.44 $4.44dolla

maria [59]

Question:

Chucky grabbed 11 items in the grocery store that each had a different price and had a mean cost of about $4.44. On his way to the register, he gave in to an impulse to add a 12th item: an entire wheel of cheese that cost $39.99.

How will adding the wheel of cheese affect the mean and median?

Answer:

There will be a big difference in the mean when the new item is added

Step-by-step explanation:

Given

$Items = 11$

$Mean = \$4.44$

Before we solve further, we need to first calculate the total amount of the 11 items.

$Mean = \frac{Total}{Items}$

Make Total the Subject of formula

$Total = Mean * Items$

$Total = \$4.44 * 11$

$Total = \$48.84$

When the 12th item of $39.99 is added, the new mean becomes.

$New\ Mean = \frac{Total + \$39.99}{11 + 1}$

$New\ Mean = \frac{\$48.84 + \$39.99}{11 + 1}$

$New\ Mean = \frac{\$88.83}{12}$

$New\ Mean = \$7.4025$

By comparing this the old mean, we can see a huge increment between $4.44 and $7.4025

This means that there will be a big difference in the mean when the new item is added.

For the Median:

The old mean shows that the prices of the 11 items is within a small range from $4.44.

So, when the new item is added the median will only change a little bit.

In other words, the median value will only change a little bit.

7 0

3 years ago

Read 2 more answers

Solve 2/3-4x+7/2=-9x+5/6 A.x=-3/2 B.x=-2/3 C.x=2/3 D.x=3/2

pav-90 [236]

The answer to the question

8 0

3 years ago

Find the largest interval which includes x = 0 for which the given initial-value problem has a unique solution. (Enter your answ

Ivan

Answer:

$(-\infty,3)$

Step-by-step explanation:

We are given that

$(x-3)y''+4y=x$

$y''+\frac{4}{x-3}y=\frac{x}{x-3}$

y(0)=0

y'(0)=1

By comparing with

$y''+p(x)y'+q(x)y=g(x)$

We get

$p(x)=\frac{4}{x-3}$

$g(x)=\frac{x}{x-3}$

q(x)=0

p(x),q(x) and g(x) are continuous for all real values of x except 3.

Interval on which p(x),q(x) and g(x) are continuous

$(-\infty,3)$ and (3, $\infty)$

By unique existence theorem

Largest interval which contains 0= $(-\infty,3)$

Hence, the larges interval on which includes x=0 for which given initial value problem has unique solution= $(-\infty,3)$

7 0

3 years ago