Answer=210 ways
Okay. I'm not entirely sure this is the BEST way to solve for this answer, but nonetheless, I'll show how I would solve the equation.
First, lets look at the probability of the two options happening. The probability of one of the 15 members becoming president is 1/15. Then, since one student is already being used for the spot of president, the odds of another student becoming vice president is 1/14.

From this, we know that there are 210 options for the positions of president and vice president total (since 210 represents the whole).
So they can choose the president and vice president 210 different ways
You could subtract 5/4 from each side of the equation.
Then it would say
x = -2/4 .
That's a perfectly true solution, but not a very attractive one.
To pretty it up, you could simplify the fraction if you felt like it,
and you would have
x = -1/2 .
6 phone numbers are possible for one area code if the first four numbers are 202-1
<u>Solution:</u>
Given that, the first four numbers are 202-1, in that order, and the last three numbers are 1-7-8 in any order
We have to find how many phone numbers are possible for one area code.
The number of way “n” objects can be arranged is given as n!
Then, we have three places which changes, so we can change these 3 places in 3! ways

Hence 3! is found as follows:

So, we have 6 phone numbers possible for one area code.
Answer:
B
Step-by-step explanation:
I hope this helped!
How many do you want me to answer? I will answer in the comments :)