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4 years ago

10

Please help and show the work please!!

1 answer:

Alinara [238K]4 years ago

8 0

Answer

39 - B. 31.4

40 - C. 9.8x+1.1y+9.9z

For 39, the formula for the circumference of a circle is $2\pi r$ where r is the radius of the circle. Substituting r=5 gives $2\pi 5=31.4$ .

For 40, you basically just add up like terms according to which variable the coefficient is in front of.

$5.5x+4.3x=9.8x\\6.2y-5.1y=1.1y\\8.3z+1.6z=9.9z\\9.8x+1.1y+9.9z$

Hope this helps.

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Given: x + 2y = -6.<br><br><br><br> Solve for y.

zavuch27 [327]

Answer:

The answer is option 3.

Step-by-step explanation:

The steps are :

$x + 2y = - 6$

$2y = -x - 6$

$y = \frac{ - x - 6}{2}$

7 0

3 years ago

Read 2 more answers

Alright to the nearest 100th now

kirill [66]

Answer:

28.26

Step-by-step explanation:

For this, we can simply use the pi times r squared because we have the radius.

simplify pi to 3.14, so we can do 3.14 times 3 squared.

we get 9x 3.14, which is 28.26.

8 0

3 years ago

8.) The grocery store is having a sale on frozen vegetables. 4 bags are being sold for $11.96. At this rate, what is the cost of

MAVERICK [17]

a) 1 bag is $2.99

b) 9 bags are $26.91.

$11.96/4 is 2.99

So one bag costs $2.99 and for any rest of number of bags we just multiply that number by 2.99!!

Hope this helps. :)

5 0

2 years ago

Read 2 more answers

Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30

TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

$-7, -3, 1, 5, . . .$

An arithmetic sequence has a constant difference d and is defined by

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4$

$\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}$

$d=4$

$\mathrm{The\:first\:element\:of\:the\:sequence\:is}$

$a_1=-7$

as

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:$

$a_n=4\left(n-1\right)-7$ ∵ $d=4$

$\mathrm{Arithmetic\:sequence\:sum\:formula:}$

$n\left(a_1+\frac{d\left(n-1\right)}{2}\right)$

$\mathrm{Plug\:in\:the\:values:}$

$n=30,\:\space a_1=-7,\:\spaced=4$

$=30\left(-7+\frac{4\left(30-1\right)}{2}\right)$

$=30\left(58-7\right)$ ∵ $\frac{4\left(30-1\right)}{2}=58$

$=30\cdot \:51$

$=1530$ ∵ $\mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530$

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

$a_n=4\left(n-1\right)-7$

n = 30

$\sum _{n=1}^{30}\:4\left(n-1\right)-7$

$=\sum _{n=1}^{30}4n-11$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n$

$=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11$

as

$\sum _{n=1}^{30}4n=1860$

and

$\sum _{n=1}^{30}11=330$

so

$=1860-330$

$=1530$

7 0

4 years ago

How do you find the solution of this proportion?<br> 4/9 = m2-1/54 <br> m2 is m to the power of 2

elena-14-01-66 [18.8K]

Answer:

±5sqrt(6)/6 = m

Step-by-step explanation:

4/9 = m^2-1/54

Add 1/54 to both sides

4/9+ 1/54 = m^2-1/54 +1/54

4/9+ 1/54 = m^2

Get a common denominator of 54

4/9 *6/6 + 1/54 = m^2

24/54 + 1/54 = m^2

25/54 = m^2

Take the square root of each side

±sqrt(25/54) = sqrt(m^2)

±sqrt(25/54) = m

±sqrt(25)/sqrt(54) = m

±sqrt(25)/sqrt(9)sqrt(6) = m

±5/3sqrt(6) = m

±5/3sqrt(6) *sqrt(6)/sqrt(6) = m

±5sqrt(6)/3*6 = m

±5sqrt(6)/6 = m

8 0

3 years ago