Answer:
B 3.78 seconds
Step-by-step explanation:
On the graph, the line ends when it hits (0,3.78) This means that the object was in the air for 3.78 seconds before hitting the ground (0 height)
first, the slope is needed, which is 3-2/3--3 which is 1/6 and so this will be y=(1/6)x+b which then we'll input (3,3) which is 3=2+b or b=1 so the equation is y=(1/6)x+1
Answer: I am pretty sure it is 7
Step-by-step explanation:
the smaller one is to smaller than the bigger one so you would just add two to the 5
<h2><u>
Answer With Explanation:</u></h2>
<u>Firstly, let's start with <XOZ: =55°</u>
We know that <ZOQ is 70° and angles on a line add up to 180° so we do 180-70=110 110 divided by 2 = 55 so the 2 angles (XOZ & XOP are 55)
<u>Secondly, <OMN, <MON & <ONM = All are 60°</u>
These 2 angles are joined to create an equilateral triangle which always adds up to 180°
So, there are 3 points to this triangle, therefore we divide 180 by 3 which is 60. The angles are 60°
<u>Thirdly, <QON: =55°</u>
This angle lies on the line XON which needs to add up to 180°
As we worked out before, <XOZ was 55°
So, <ZOQ was already given as 70°
We then do 55+70=125 then 180-125=55°
<QON is 55°
(I'm only in Grade 9 LOL)
