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kozerog [31]
3 years ago
7

Given: x + 2y = -6. Solve for y.

Mathematics
2 answers:
zavuch27 [327]3 years ago
7 0

Answer:

The answer is option 3.

Step-by-step explanation:

The steps are :

x + 2y =  - 6

2y =  -x - 6

y =  \frac{ - x - 6}{2}

Drupady [299]3 years ago
7 0

Answer: choice #3

x + 2y = -6

2y = -6 - x      [ subtract x from both sides ]

y = (-6 - x)/2   [ isolate y ]

y = (-x - 6)/2 [ rearrange numerator ]

The answer choice that matches this is the third one, i hope this helps! :D

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Harlamova29_29 [7]

I typed right on the problem set.

4 0
2 years ago
HELP!!!!
ss7ja [257]
<h3>3 Answers: Choice D, Choice E, Choice F</h3>

============================================================

Explanation:

The inequality 6x - 10y ≥ 9 solves to y ≤ (3/5)x - 9/10 when you isolate y.

Graph the line y = (3/5)x - 9/10 and make this a solid line. The boundary line is solid due to the "or equal to" as part of the inequality sign. We shade below the boundary line because of the "less than" after we isolated for y.

Now graph all of the points given as I've done so in the diagram below. The points in the blue shaded region, or on the boundary line, are part of the solution set. Those points are D, E and F.

We can verify this algebraically. For instance, if we weren't sure point E was  a solution or not, we would plug the coordinates into the inequality to get...

6x - 10y ≥ 9

6(5) - 10(2) ≥ 9 .... plug in (x,y) = (5,2)

30 - 20 ≥ 9

10 ≥ 9 ... this is a true statement

Since we end up with a true statement, this verifies point E is one of the solutions. I'll let you check points D and F.

-----------

I'll show an example of something that doesn't work. Let's pick on point A.

We'll plug in (x,y) = (-1,1)

6x - 10y ≥ 9

6(-1) - 10(1) ≥ 9

-6 - 10 ≥ 9

-16 ≥ 9

The last inequality is false because -16 is smaller than 9. So this shows point A is not a solution. Choices B and C are non-solutions for similar reasons.

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Answer:

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