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3 years ago

3 x 1/3 divided by 2 x 3 to the second power

Mathematics

1 answer:

BabaBlast [244]3 years ago

6 0

Answer:

1/36

Step-by-step explanation:

3(1/3)=3/3=1

2*3=6

(1/6)^2=(1/6)(1/6)=1/36

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Miri counted her money and found that her 25 coins which were nickels, dimes, and quarters were worth $3.20. the number of dimes

Natasha_Volkova [10]

Nickels = x

dimes = x + 4

quarters = x

Value of coins:

nickel = 5 cents

dime = 10 cents

quarter = 25 cents

5x + 10(x + 4) + 25x = 3.20

5x + 10x + 40 + 25x = 320

40x = 320 - 40

40x = 280

x = 280/40

x = 7

There are 7 quarters, 7 nickels and 11 dimes.

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3 years ago

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3v - 18. I hope this helped

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3 years ago

Read 2 more answers

How many liters of water must Sharon add to 2 liters of a sugar and water solution that is 36% sugar to create a solution that i

Dahasolnce [82]

The amount of sugar $x$ in the starting solution contributes to a 36% concentration, so we have

$\dfrac x2=0.36\implies x=0.64$

units of sugar in the solution.

Into this solution, Sharon wants to pour $y$ liters of water to obtain a smaller concentration of sugar in the overall solution:

$\dfrac{0.64}{2+y}=0.12\implies\dfrac{16}3=2+y\implies y=\dfrac{10}3\approx3.33$

So Sharon needs to add $\dfrac{10}3$ liters of water to the solution to get the desired concentration.

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4 years ago

How to do question 1?Had no idea how to do both parts

givi [52]

$y=\dfrac{\ln x}{3x-6}$

Differentiate both sides with respect to $x$ :

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}$

When $x=1$ , you have

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}=\dfrac{-3}9=-\dfrac13$

For part (b), we now assume that $x$ and $y$ are functions of an independent variable, which we'll call $t$ (for time). Now differentiating both sides with respect to $t$ , we have

$\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}\dfrac{\mathrm dx}{\mathrm dt}$

where the chain rule is used on the right side. We're told that $y$ is decreasing at a constant rate of 0.1 units/second, which translates to $\dfrac{\mathrm dy}{\mathrm dt}=-0.1$ . So when $x=1$ , you have

$-0.1=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}\dfrac{\mathrm dx}{\mathrm dt}$
$-0.1=-\dfrac13\dfrac{\mathrm dx}{\mathrm dt}$
$\dfrac{\mathrm dx}{\mathrm dt}=0.3$

where the unit is again units/second.

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago