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miv72 [106K]
3 years ago
8

What is 400,000 rounded to 100,000

Mathematics
1 answer:
Goryan [66]3 years ago
7 0
The same number rounded to the nearest ten thousand is 350,000.
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A container has 1 pink block and 3 green blocks. Juan wants to make the probability of randomly selecting a black block equal to
alex41 [277]

Answer:

4

Step-by-step explanation:

He should add 4 black blocks because there are a total of 4 other blocks, and in order to have a probability of 50%, the number of black blocks needs to be equal to the total number of the other colored blocks.

8 0
3 years ago
An airplane flies into the wind for 5 hours, traveling 900 miles. The airplane then
Musya8 [376]

Answer:

22.5 miles per hour

Step-by-step explanation:

<u>Given system of equations</u>

5(s-w)=900

4(s+w)=900

<u />

<u>Set equations equal to each other</u>

5(s-w)=4(s+w)

5s-5w=4s+4w

s-5w=4w

s=9w

<u>Solve for w using the substitution s=9w</u>

4(s+w)=900

4(9w+w)=900

4(10w)=900

40w=900

w=22.5

Therefore, the speed of the wind is 22.5 miles per hour

7 0
2 years ago
Can someone help me with these?​
Jet001 [13]
48 is the correct answer because your going to only do the square
4 0
3 years ago
Read 2 more answers
A balloon flying at 3000 feet above the ocean measures the angles of depression of each end of an island directly in front of th
saul85 [17]
The length of the island will be given as follows:
tan θ=opposite/adjacent
thus:
tan75.8= 3000/a1
a1=3000tan75.8
a1=11855.885 ft

also:
tan15.6=3000/a2
a2=3000tan15.6
a2=837.62 ft
Thus the length of the island will be:
11855.885-837.615
=11,018.24 ft
3 0
3 years ago
Basic Computation: Find Probabilities In Problems 5-14, assume that x has a normal distribution with the specified mean and stan
Ulleksa [173]

Answer:

the answer is below

Step-by-step explanation:

The z score is used to calculate by how many standard deviations the raw score is above or below the mean. The z score is given as:

z=\frac{x-\mu}{\sigma}\\\\\mu=mean,\sigma=standard\ deviation

1) For x = 3

z=\frac{x-\mu}{\sigma}=\frac{3-4}{2}=-0.5

For x = 6

z=\frac{x-\mu}{\sigma}=\frac{6-4}{2}=1

P(3 ≤ x ≤ 6) = P(-0.5 ≤ z ≤ 1) = P(z < 1) - P(z < -0.5) = 0.8413 - 0.3085 = 0.5328

2) For x = 50

z=\frac{x-\mu}{\sigma}=\frac{50-40}{15}=0.67

For x = 70

z=\frac{x-\mu}{\sigma}=\frac{70-40}{15}=2

P(50 ≤ x ≤ 70) = P(0.67 ≤ z ≤ 2) = P(z < 2) - P(z < 0.67) = 0.9772 - 0.7486 = 0.2286

3) For x = 8

z=\frac{x-\mu}{\sigma}=\frac{8-15}{3.2}=-2.19

For x = 12

z=\frac{x-\mu}{\sigma}=\frac{12-15}{3.2}=-0.94

P(8 ≤ x ≤ 12) = P(-2.19 ≤ z ≤ -0.94) = P(z < -0.94) - P(z < -2.19) = 0.1736 - 0.0143 = 0.1593

4) For x = 30

z=\frac{x-\mu}{\sigma}=\frac{30-20}{3.4}=2.94

P(x ≥ 30) = P(z ≥ 2.94) = 1 - P(z < 2.94) = 1 - 0.9984 = 0.0016

5)  x = 90

z=\frac{x-\mu}{\sigma}=\frac{90-100}{15}=-0.67

P(x ≥ 90) = P(z ≥ -0.67) = 1 - P(z < -0.67) = 1 - 0.2514 = 0.7486

6)  For x = 10

z=\frac{x-\mu}{\sigma}=\frac{10-15}{4}=-1.25

For x = 20

z=\frac{x-\mu}{\sigma}=\frac{20-15}{4}=1.25

P(10 ≤ x ≤ 20) = P(-1.25 ≤ z ≤ 1.25) = P(z < 1.25) - P(z < -1.25) = 0.8944 - 0.1056 = 0.7888

7)  For x = 7

z=\frac{x-\mu}{\sigma}=\frac{7-5}{1.2}=1.67

For x = 9

z=\frac{x-\mu}{\sigma}=\frac{9-5}{1.2}=3.33

P(7 ≤ x ≤ 9) = P(1.67 ≤ z ≤ 3.33) = P(z < 3.33) - P(z < 1.67) = 0.9996 - 0.9525 = 0.0471

8)  For x = 40

z=\frac{x-\mu}{\sigma}=\frac{40-50}{15}=-0.67

For x = 47

z=\frac{x-\mu}{\sigma}=\frac{47-50}{15}=-0.2

P(40 ≤ x ≤ 47) = P(-0.67 ≤ z ≤ -0.2) = P(z < -0.2) - P(z < -0.67) = 0.4207 - 0.2514 = 0.1693

9)  x = 120

z=\frac{x-\mu}{\sigma}=\frac{120-10}{15}=7.33

P(x ≥ 120) = P(z ≥ 7.33) = 1 - P(z < 7.33) = 1 - 0.9999 = 0.001

10) x = 2

z=\frac{x-\mu}{\sigma}=\frac{2-3}{0.25}=-4

P(x ≥ 2) = P(z ≥ -4) = 1 - P(z < -4) = 1 - 0.0001 = 0.999

3 0
3 years ago
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