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katovenus [111]
3 years ago
8

Solve the system of equations by substitution y=5x-13 and 5x+2y=19

Mathematics
1 answer:
castortr0y [4]3 years ago
6 0
Y = 5x - 13 ----------- (1)
5x + 2y = 19 --------- (2)

Sub (1) into (2):

5x + 2(5x -13) = 19
5x + 10x - 26 = 19
15x = 19 + 26
15x = 45
x = 3 -------- sub back into (1)
y = 5(3) - 13
y = 15 - 13
 y = 2

Ans: x = 3, y = 2
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The area of a rectangle is 91 square inches. If the length of the rectangle is 1 less than twice its width, write an equation th
Ahat [919]

The following equation can be used to calculate the width, w, of the rectangle with the specified area: 2w²- w - 91 = 0.

<h3>What is a Rectangle's Area?</h3>

rectangle area = length width

Multiply the length by the width to obtain the area of a rectangle. The formula is as follows: A = L * W where A is the area, L denotes the length, W denotes the width, and * denotes multiplication. where A denotes area, s denotes side length, and implies multiply.

Given,

Rectangle area = 91 in.

2 w = width

The rectangle's length equals 2w - 1.

Using the area formula, the equation for calculating w would be: (2w - 1)(w) = 91.

2w² - w - 91 = 0

As a result, the equation for determining the width, w, of the rectangle with the specified area is: 2w² - w - 91 = 0.

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5 0
1 year ago
What is the equation of the line passing through the points (–25, 50) and (25, 50) in slope-intercept form?
allochka39001 [22]

The equation of the line passing through the points (-25, 50) and (25, 50) in slope-intercept form is <u>y = 50</u>. Hence, <u>4th option</u> is the right choice.

The slope-intercept form of a line is written as y = mx + b, where m is the slope of the line, and b is the y-intercept.

The slope of a line passing through the points (x₁, y₁) and (x₂, y₂) can be calculated using the formula, slope (m) = (y₂ - y₁)/(x₂ - x₁).

Therefore, slope of the line passing through the points (-25, 50) and (25, 50) can be calculated as m = (50 - 50)/(25 - (-25)) = 0/(-50) = 0.

We can find the equation of the line using the point-slope formula, according to which, a line having a slope m and passing through the point (x₁, y₁) can be written as y - y₁ = m(x - x₁).

Therefore, the equation of the given line can be written as:

y - 50 = 0(x - 25)

or, y - 50 = 0,

or, y = 50.

Therefore, the equation of the line passing through the points (-25, 50) and (25, 50) in slope-intercept form is <u>y = 50</u>. Hence, <u>4th option</u> is the right choice.

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3 0
2 years ago
Which of the following is not a congruence transformation?
Hatshy [7]
The following that is not a congruence transformation is A, stretching.
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3 years ago
Solve the following inequality for x. -5x&lt;-15x+40
melisa1 [442]

Answer:

x is less than 4

or

x is greater than 4

Step-by-step explanation:

-5x < -15x + 40 -5x < -15x + 40

+15x +15x -40 -40

10x < 40 -40 - 5x < -15x

÷10 ÷10 +5x +5x

× < 4 -40 < -10x

÷10 ÷10

4 < ×

5 0
3 years ago
H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.
natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

<h3>Given information-</h3>

The given function is,

h(x)=x^2+1

k(x)=x-2

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

(h+k)(x)=h(x)+k(x)

(h+k)(x)=x^2+1+x-2

(h+k)(2)=2^2+1+2-2

(h+k)(x)=5

2)The value of the function (h-k)(3),

(h-k)(x)=h(x)-k(x)

(h-k)(x)=x^2+1-x+2

(h-k)(3)=3^2+1-3+2

(h-k)(x)=9

3) The value of the function 3h(2)+2k(3)

3h(x)+2k(x)=3x^2+3+2x-2\times 2

3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2

3h(2)+2k(3)=17

Hence the value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

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4 0
2 years ago
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