Solve the system of equations by substitution y=5x-13 and 5x+2y=19
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Hey,
2x^2 + 3root5x + 5
Here the product=10
And,sum=3root5
=>2x^2+2root5x+root5x+5
=>2x(x+root5)+ root5(x+root5)
=>(2x+root5)(x+root 5)
2x^2 + 3root5x + 5
Here the product=10
And,sum=3root5
=>2x^2+2root5x+root5x+5
=>2x(x+root5)+ root5(x+root5)
=>(2x+root5)(x+root 5)
Hi there!
Since we have 2 variables in the given equation, and you only want to solve for one, the other will end up in your answer.
Step 1) Add 8y to both sides.
Step 2) Divide both sides by 6.
Final Answer -
Hope this helps! :D