Answer:
-75
Step-by-step explanation:
Let us consider the first odd number to be 'x'.
Thus:
- 1st odd number: x
- 2nd odd number: x+2
- 3rd odd number: x+3
According to the question, the sum of these three consecutive ODD numbers should be equal to -219
So,
x + x + 2 + x + 4 = -219
3x + 6 = -219
3x = -225
x = -75
Y=1/3x+1 is the equation for ur question
n, n + 1, n + 2, n + 3 - four consecutive integers
-142 - the sum
The equation:
n + (n + 1) + (n + 2) + (n + 3) = -142
n + n + 1 + n + 2 + n + 3 = -142
4n + 6 = -142 |subtract 6 from both sides
4n = -148 |divide both sides by 4
n = -37
n + 1 = -37 + 1 = -36
n + 2 = -37 + 2 = -35
n + 3 = -37 + 3 = -34
Answer: -37, -36, -35, -34.
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Answer:
z=16
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
−7(z−6)=−70
(−7)(z)+(−7)(−6)=−70(Distribute)
−7z+42=−70
Step 2: Subtract 42 from both sides.
−7z+42−42=−70−42
−7z=−112
Step 3: Divide both sides by -7.
−7z
/−7
=
−112
/−7
z=16
