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zepelin [54]
3 years ago
10

PLEASE HELP.

Mathematics
1 answer:
solniwko [45]3 years ago
5 0

recall that the radius is the distance from the center of a circle to any point on the circle.

we know the center is at -16,-14, and we know that -8,-8 is a point on the circle, so the distance between both must be the radius.


\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-16}~,~\stackrel{y_1}{-14})\qquad
(\stackrel{x_2}{-8}~,~\stackrel{y_2}{-8})\qquad \qquad
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
\stackrel{radius}{r}=\sqrt{[-8-(-16)]^2+[-8-(-14)]^2}
\\\\\\
r=\sqrt{(-8+16)^2+(-8+14)^2}\implies r=\sqrt{8^2+6^2}
\\\\\\
r=\sqrt{100}\implies \boxed{r=10}
\\\\[-0.35em]
\rule{34em}{0.25pt}


\bf \textit{equation of a circle}\\\\
(x- h)^2+(y- k)^2= r^2
\qquad
center~~(\stackrel{-16}{ h},\stackrel{-14}{ k})\qquad \qquad
radius=\stackrel{10}{ r}
\\\\\\\
[x-(-16)]^2+[y-(-14)]^2=10^2\implies \blacktriangleright (x+16)^2+(y+14)^2=100 \blacktriangleleft

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zheka24 [161]

Answer:

B. x ≤ 5

Step-by-step explanation:

This is an inequality problem. It can be solved by examining the arrow and the point it closes on. If the arrow is going left, then all values of x are going to be <u>less than</u> the point it closes on. If the arrow is going right, then all values of x are going to be <u>greater than</u> the point it closes on.
If the circle on the point the arrow is closed/shaded in, then that value will be included in the values of x, giving the inequality either a ≤ or ≥ sign depending on which way the arrow is pointing. If the circle on the point the arrow is open, then that value will not be included in the values of x. The sign will be either < or >.

---------------------------------------------------------------------------

For this problem, the arrow is going to the left of 5, which means all values of x are going to be less than 5. Because the circle is closed, that means that number 5 is included, or x can be equal to 5. If the circle was open, it wouldn't be included. So, the inequality is x ≤ 5.

hope this helps!

7 0
2 years ago
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Viktor [21]
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5 0
3 years ago
Building A is 464 feet tall and Building B is 321 feet tall. Dale is standing between the buildings. The angle of elevation from
alex41 [277]

Answer:

The distance between the buildings is:

D = 413.3 ft

Step-by-step explanation:

Ok, here we have two triangle rectangles, such that these triangle rectangles share a common vertex which is Dale.

One of the triangles, let's call it triangle A, has the catheti:

Distance between Dale and Building A = d1

Height of Building A = 464 ft

The other triangle (triangle B) has the catheti:

Distance between Dale and Building B = d2

Height of building B = 321ft

We want to find the distance between the buildings, which is equal to d1 + d2.

Then we want to find d1 and d2.

For triangle A:

We know that the angle at the vertex where Dale is standing, is 75°

Then the adjacent cathetus is d1, and the opposite cathetus is the height of building A.

Remember that:

Tan(θ) = (opposite cathetus)/(adjacent cathetus)

Then:

Tan(75°) = (464 ft)/(d1)

d1 = (464 ft)/(Tan(75°)) = 124.3 ft

Now for triangle B, the angle at the vertex where Dale is standing is 48°.

from this vertex, we have d2 as the adjacent cathetus and the height of build B as the opposite cathetus.

Then:

Tan(48°) = 321ft/d2

d2 = (321ft)/(Tan(48°)) = 289ft

Then the distance between the buildings is:

D = d1 + d2 =  124.3 ft +  289ft = 413.3 ft

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mariarad [96]
I hope this helps you

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