Answer:
Time it took for the walker to land on net = 1.75 seconds
Step-by-step explanation:
Given:
Height above the ring as a function of time is give as:
![h(t)=60-16t^2](https://tex.z-dn.net/?f=h%28t%29%3D60-16t%5E2)
Height of the tightrope walker after he falls = 11 feet
Plugging the height in order to find the time it took for the walker to land on net.
![11=60-16t^2](https://tex.z-dn.net/?f=11%3D60-16t%5E2)
Adding
to both sides.
![11+16t^2=60-16t^2+16t^2](https://tex.z-dn.net/?f=11%2B16t%5E2%3D60-16t%5E2%2B16t%5E2)
![11+16t^2=60](https://tex.z-dn.net/?f=11%2B16t%5E2%3D60)
Subtracting both sides by 11.
![11-11+16t^2=60-11](https://tex.z-dn.net/?f=11-11%2B16t%5E2%3D60-11)
![16t^2=49](https://tex.z-dn.net/?f=16t%5E2%3D49)
Dividing both sides by 16.
![\frac{16t^2}{16}=\frac{49}{16}\\\\t^2=\frac{49}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B16t%5E2%7D%7B16%7D%3D%5Cfrac%7B49%7D%7B16%7D%5C%5C%5C%5Ct%5E2%3D%5Cfrac%7B49%7D%7B16%7D)
Taking square root both sides.
![\sqrt t^2=\sqrt{\frac{49}{16}}\\\\t=\pm\frac{7}{4}](https://tex.z-dn.net/?f=%5Csqrt%20t%5E2%3D%5Csqrt%7B%5Cfrac%7B49%7D%7B16%7D%7D%5C%5C%5C%5Ct%3D%5Cpm%5Cfrac%7B7%7D%7B4%7D)
Since time is always positive
∴ ![t=\frac{7}{4} = 1.75 \ seconds](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B7%7D%7B4%7D%20%3D%201.75%20%5C%20seconds)
∴ Time it took for the walker to land on net = 1.75 seconds
A trampoline park or an arcade
Answer:
1/12 foot
Step-by-step explanation:
Answer:
Three-fourths a less-than-or-equal-to 15
Step-by-step explanation:
Hope this helps!
Answer:
1.8 million
Step-by-step explanation:
Add everything up to get 9 million, then divide by 5 to get the average of the years. This leaves you with 1.8 million