Question

A line has a slope of 1 and passes through the point (14, 0). What is its equation in

Answer 1

Answer:

y = x - 14

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = 1, thus

y = x + c ← is the partial equation of the line

To find c substitute (14, 0) into the partial equation

0 = 14 + c ⇒ c = 0 - 14 = - 14

y = x - 14 ← equation in slope- intercept form

Answer 2

Answer: $y=x-14$

Step-by-step explanation:

We know that the equation of a line passing through a point (a,b) and has slope m is given by :-

$(y-b)=m(x-a)$

Given : A line has a slope of 1 and passes through the point (14, 0).

Then, the equation of line will be :-

$(y-0)=(1)(x-14)\\\\\Rightarrow\ y=x-14$

Also, the equation is of line in intercept form is $y=mx+c$

Hence, the equation of given line in  slope-intercept form is $y=x-14$.