Let C be the nullspace of the 1 x 9 matrix H1 (6.2.6) In other words, let C be the parity check code of length 9 (8 data bits, 1
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Answer: (c) x = -4
Let's look at an example:
2.24 x 21.6
Do normal multiplication and get
48384 This is not correct, until we put the decimals in. To know how to do this, count the number of decimal spaces from the factors. In 2.24, there are 2, because .24. In 21.6 there are 1 because of .6. This mean three places, so 48384 becomes
48.384
~theLocoCoco