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Luda [366]
2 years ago
6

Please answer all there. Need help fast

Mathematics
2 answers:
Leto [7]2 years ago
6 0
Oh yeah yeah 9272918919171918
ddd [48]2 years ago
3 0
Answer 1.)is 196 simplify 7^2 to 49 6*(49-15)-2^3. Do 49-15=34 6*34-2^3. Do 2^3 to 8 6*34-8 =204-8 which is 196 hope this helps you
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Write an equation in Standard Form. A store sells t-shirts for $12 each and
Dmitrij [34]
Standard form: Ax + By = C
Equation: 12x + 15y = 120
8 0
2 years ago
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2. At 1 pm, you leave Ellensburg at a constant speed of 75 miles per hour. At 2:30 pm, your
MA_775_DIABLO [31]

Here, we are required to determine how many hours your friend will drive in order to catch you.

(a)<em> Your friend will have to drive 7 and a half hours inorder to catch </em><em>you.</em>

<em>(</em><em>b)</em><em> </em><em>You </em><em>both </em><em>will </em><em>be </em><em>6</em><em>7</em><em>5</em><em> </em><em>miles</em> <em>away </em><em>from </em><em>Ellensburg</em><em> </em><em>at </em><em>that </em><em>time.</em>

If you leave at 1 pm; At 2:30pm;

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Therefore, your position; S after 2:30pm is given by;

S(a) = 75t + 112.5 miles from Ellensburg.

For your friend; travelling at 90miles/hr;

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(a) For your friend to catch you, you both must be in the same position;

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75t + 112.5 = 90t

90t -75t = 112.5

t = 112.5/15

t = 7.5hours

(b) To determine how far you both are from Ellensburg; we can either evaluate:

S(b) = 90t or S(a) = 75t + 112.5

Therefore, By evaluating S(b) = 90t.

S(b) = 90 × 7.5

S(b) = 675miles from Ellensburg.

Read more:

brainly.com/question/24234606

6 0
1 year ago
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Among 46​- to 51​-year-olds, 28​% say they have called a talk show while under the influence of peer pressurepeer pressure. Supp
sasho [114]

Answer:

0.8997, 0.9999

Step-by-step explanation:

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Each person is independent of the other and there are only two outcomes

n =7

a) the probability that at least one has not called a talk showcalled a talk show while under the influence of peer pressure

=P(Y\geq 1) where Y is binomial with p = 0.72

= 1-(1-0.72)^7\\=0.9999

b) the probability that at least one has  called a talk showcalled a talk show while under the influence of peer pressurepeer pressurethe probability that at least one has not called a talk showcalled a talk show while under the influence of peer pressure

=P(x\geq 1) =1-P(0)\\= 1-(1-0.28)^7\\=0.8997

3 0
2 years ago
Good morning! Can any math expert help me with this thank you
Rasek [7]
The anwser is 29 !!!!!
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one method for deciding between two chioces is to toss a coin. what are all the possible outcomes when you toss a coin?
Arte-miy333 [17]
Either heads or tails so there is a 50/50 chance of both
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2 years ago
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