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KengaRu [80]
3 years ago
5

∠1 and ∠2 are

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
6 0

Answer:

they are complementary angles

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Write the measurements of Sides AB, BC, and CD of the correct net.
scZoUnD [109]
AB- 3in.
BC- 5in.
CD- 7.2in.

sorry i don't really have an explanation I just looked at the picture and i guess imagined it in my head? lol sorry but here are the answers I hope that helps at least a little bit :))
8 0
2 years ago
Read 2 more answers
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
2 years ago
What’s that precent 250 of 275
tester [92]

Answer:

Percent 250 of 275 is 90.9%

Step-by-step explanation:

We have to find 250 is what percent of 275.

Let X be the percentage, then

=> X =  \frac{250}{275} \times 100

Now simplyfying the above relation we get

=> X =  0.909\times 100

=> => X = 90.9 %

Hence 250 is 90.9% of 275

5 0
3 years ago
Solve x ^3 = 125 for x. You can see the graph of the equation y = x ^3 - 125 below.
Harrizon [31]
\bf x^3=125\implies x=\sqrt[3]{125}\implies x=5
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3 years ago
Find an expression in simplest form for the verbal description. The total pay for 12 hours of work at a base rate of P per hour
Jobisdone [24]
Base:
12 \times p = 12p  \\
Bonus:
12 \times 1.50
Total:
12 \times (p + 1.50)
6 0
2 years ago
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