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Mama L [17]
3 years ago
15

Using the formula n3 +1 find the first three terms​

Mathematics
1 answer:
netineya [11]3 years ago
3 0

Answer:

2, 9, 28

Step-by-step explanation:

To find the first 3 terms substitute n = 1, 2, 3 into the formula, that is

1³ + 1 = 1 + 1 = 2

2³ + 1 = 8 + 1 = 9

3³ + 1 = 27 + 1 = 28

The first 3 terms are 2, 9, 28

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Answer:

z = -1.53 --- test statistic

p = 0.1260 --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

n_1 = 80     \bar x_1= 104   \sigma_1 = 8.4

n_2 = 70    \bar x_2 = 106    \sigma_2 = 7.6

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H_a: \mu_1 - \mu_2 \ne 0 ---- Alternate hypothesis

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This is calculated as:

z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}

So, we have:

z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}

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z = \frac{-2}{\sqrt{1.7071}}

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Solving (b): The p value

This is calculated as:

p = 2 * P(Z < z)

So, we have:

p = 2 * P(Z < -1.53)

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We have:

\alpha = 0.05

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p = 0.1260

By comparison:

p > \alpha

i.e.

0.1260 > 0.05

So, we fail to reject the null hypothesis.

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