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iragen [17]
3 years ago
5

Solve a triangle when A = 27.3°, B = 55.9°, and a = 8.6.

Mathematics
2 answers:
padilas [110]3 years ago
8 0

Answer:

The correct answer is A.

Step-by-step explanation:

i just did the test on edge and got it right, it’s not D, it’s A.

lys-0071 [83]3 years ago
3 0

Answer:

d

Step-by-step explanation:

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I need to find the volume of the cylinder
masha68 [24]

Answer:

depends on what kinda cylinder your starting to find a answer to

3 0
3 years ago
Would you need to use the chain rule to find the derivative of this function?
Nutka1998 [239]

Answer:

TRUE. We need to use the chain rule to find the derivative of the given function.

Step-by-step explanation:

Chain rule to find the derivative,

We have to find the derivative of F(x)

If F(x) = f[g(x)]

Then F'(x) = f'[g(x)].g'(x)

Given function is,

y = \sqrt{2x+3}

Here g(x) = (2x + 3)

and f[g(x)] = \sqrt{2x+3}

\frac{dy}{dx}=\frac{d}{dx}(\sqrt{2x+3}).\frac{d}{dx} (2x+3)

y' = \frac{1}{2}(2x+3)^{(1-\frac{1}{2})}.(2)

   = (2x+3)^{-\frac{1}{2}}

y' = \frac{1}{\sqrt{2x+3}}

Therefore, it's true that we need to use the chain rule to find the derivative of the given function.

8 0
4 years ago
Please help MEE!!! this is due tonight :(
MAVERICK [17]

Answer:

5.5g + 1

Step-by-step explanation:

i dont have time to explain

5 0
3 years ago
Read 2 more answers
Describe and correct the error(s) made in each of the problems below.
ladessa [460]

Answer:

\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}

\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}

Step-by-step explanation:

<u>Errors in Algebraic Operations </u>

It's usual that students make mistakes when misunderstanding the application of algebra's basic rules. Here we have two of them

  • When we change the signs of all the terms of a polynomial, the expression must be preceded by a negative sign
  • When multiplying negative and positive quantities, if the number of negatives is odd, the result is negative. If the number of negatives is even, the result is positive.
  • Not to confuse product of fractions with the sum of fractions. Rules are quite different

The first expression is

1-x / (5-x)(-x)=x-1 / x(x-5)

Let's arrange into format:

\displaystyle \frac{1-x}{(5-x)(-x)} =\frac{x-1 }{ x(x-5)}

We can clearly see in all of the factors in the expression the signs were changed correctly, but the result should have been preceeded with a negative sign, because it makes 3 (odd number) negatives, resulting in a negative expression. The correct form is

\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}

Now for the second expression

5/s+2/5=2/s

Let's arrange into format

\displaystyle \frac{5}{s}+\frac{2}{5} =\frac{2}{s}

It's a clear mistake because it was asssumed a product of fractions instead of a SUM of fractions. If the result was correct, then the expression should have been

\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}

6 0
3 years ago
If 4x^2-100=0 the roots of the equation are
Marrrta [24]

Your equation:                   4x² - 100           =  0

Factor the left side:      (2x + 10) · (2x - 10) = 0

This equation is true if either factor is zero.

-- One factor:                     2x + 10 = 0
  
Divide each side by 2:            x + 5 = 0
Subtract 5 from each side:      x      = -5 .


-- The other factor:               2x - 10  =  0

Divide each side by 2:            x + 5 = 0
Add  5  to each side:              x      =  5 .

8 0
3 years ago
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