Answer:
Step-by-step explanation:
y=x²-2x-1
and y=-3x+5
x²-2x-1=-3x+5
x²+x-6=0
x²+3x-2x-6=0
x(x+3)-2(x+3)=0
(x+3)(x-2)=0
x=-3,2
when x=-3
y=-3×-3+5=9+5=14
when x=2
y=-3×2+5=-6+5=-1
so solutions are (-3,14) and (2,-1)
The work done by the gas when the gas expands will be 567.65 ft-lb.
<h3>What is the work done for an isothermal process?</h3>
The Pressure is inversely proportional to the volume.
Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.
Then the work done by the gas will be
WD = P₁ V₁ ln (V₂ / V₁)
A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.
The gas expands to a volume of 3 cubic feet.
Then the work done by the gas will be
WD = 700 x 2 x ln (3/2)
WD = 1400 x 0.405
WD = 567.65 ft-lb
The work done by the gas when the gas expands will be 567.65 ft-lb.
More about the work done for isothermal process link is given below.
brainly.com/question/4218306
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A) just change the numerator to anything more than 1
B) y=1/4+1
Answer:
be more specific
Step-by-step explanation:
For me to answer it