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Marta_Voda [28]
2 years ago
13

Does anyone wanna help a gal out with this 6th grade work due today

Mathematics
1 answer:
lidiya [134]2 years ago
6 0

Answer:

2 - 30ft²

3 - 57yd²

Step-by-step explanation:

Hey There!

The first step in solving this problem is finding the formula for area of a trapezoid

A = \frac{a+b}{2} h

a = base 1

b = base 2

h = height

For the first one the dimensions are

a = 6

b = 9

h = 4

now we just plug in the values

A=\frac{6+9}{2} 4\\6+9=15\\\frac{15}{2}=7.5\\7.5*4=30

so the area of the first trapezoid is 30 ft²

For the second one the given dimensions are

a = 8

b = 11

h = 6

now we just plug in the values

A=\frac{8+11}{2} 6\\8+11=19\\\frac{19}{2} =9.5\\9.5*6=57

so the area of the second trapezoid is 57 yd²

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Y=x^2-2x-1 and y=-3x+5 solved algebraically
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Answer:

Step-by-step explanation:

y=x²-2x-1

and y=-3x+5

x²-2x-1=-3x+5

x²+x-6=0

x²+3x-2x-6=0

x(x+3)-2(x+3)=0

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y=-3×-3+5=9+5=14

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3 years ago
Find the work done by gas?
salantis [7]

The work done by the gas when the gas expands will be 567.65 ft-lb.

<h3>What is the work done for an isothermal process?</h3>

The Pressure is inversely proportional to the volume.

Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.

Then the work done by the gas will be

WD = P₁ V₁ ln (V₂ / V₁)

A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.

The gas expands to a volume of 3 cubic feet.

Then the work done by the gas will be

WD = 700 x 2 x ln (3/2)

WD = 1400 x 0.405

WD = 567.65 ft-lb

The work done by the gas when the gas expands will be 567.65 ft-lb.

More about the work done for isothermal process link is given below.

brainly.com/question/4218306

#SPJ1

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