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Komok [63]
3 years ago
9

A new piece of laboratory equipment costing $10,000 promises to save $4000 per year in materials and overtime pay. If the cost o

f money is 12% and projects must have a 3-year discounted payback period, should the equipment be purchased?
Mathematics
1 answer:
devlian [24]3 years ago
6 0

Answer:

YES, the equipment should be purchased

Step-by-step explanation:

You borrow $10000 for the piece of laboratory and the cost of money is 12%. After 3 years you will need to pay the $10000 you borrowed and the extra amount caused by the interest. 12% of $10000 if $1200, so you will end up having to pay $10000+$1200 = $11200. In three years your equipment saves you $4000*3 = $12000, which is bigger than the amount you have to pay. So, in the end the equipment should be purchased because it gives you a gain of $800.  

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kobusy [5.1K]
Your answer would be C. x = 6, y = 5
This is because if you plug the numbers in to the inequality, we get:
(4 × 5) ≥ (3 × 6) + 2
20 ≥ 18 + 2
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which is correct.

I hope this helps!
5 0
3 years ago
Read 2 more answers
one-third of the people from country A claim that they are from country B, and the rest admit they are from country A. One-fourt
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Answer: 3 : 2

Step-by-step explanation:

Let A represents the total population of country A and B represents the total population of country B.

According to the question,

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⇒ \text{ The population of A that admit they are from country A }= A - \frac{1}{3} \text{ of } A

= \frac{3-1}{3} A

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\text{The population of country B that admit they are from A} = \frac{1}{4}\text{ of }B

⇒ \text{ The total population that claims that they are from A }= \frac{2}{3} A +\frac{1}{4} B

But, Again according to the question,

The total population that claims that they are from A =  one half of the total population of A and B.

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}(A+B)

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B

⇒ \frac{2}{3} A - \frac{1}{2}A= \frac{1}{2}B-\frac{1}{4} B

⇒ \frac{4}{6} A - \frac{3}{6}A= \frac{2}{4}B-\frac{1}{4} B

⇒ \frac{1}{6} A = \frac{1}{4} B

⇒ A =\frac{6}{4}B

⇒ \frac{A}{B} =\frac{3}{2}

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3 years ago
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Step-by-step explanation:

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