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Komok [63]
3 years ago
9

A new piece of laboratory equipment costing $10,000 promises to save $4000 per year in materials and overtime pay. If the cost o

f money is 12% and projects must have a 3-year discounted payback period, should the equipment be purchased?
Mathematics
1 answer:
devlian [24]3 years ago
6 0

Answer:

YES, the equipment should be purchased

Step-by-step explanation:

You borrow $10000 for the piece of laboratory and the cost of money is 12%. After 3 years you will need to pay the $10000 you borrowed and the extra amount caused by the interest. 12% of $10000 if $1200, so you will end up having to pay $10000+$1200 = $11200. In three years your equipment saves you $4000*3 = $12000, which is bigger than the amount you have to pay. So, in the end the equipment should be purchased because it gives you a gain of $800.  

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Leilany was on a treadmill and ran 1 mile in 9 minutes. How many minutes will it take her to run 3 miles?
IRINA_888 [86]

Answer:

27

Step-by-step explanation:

1 mile took 9 min to run, so 3 miles will be:

3 x 9 =

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4 0
3 years ago
A candy maker produces mints that have a label weight of 20.4 grams. Assume that the distribution of the weights of these mints
Sliva [168]

Answer:

a)0.099834

b) 0

Step-by-step explanation:

To solve for this question we would be using , z.score formula.

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

A candy maker produces mints that have a label weight of 20.4 grams. Assume that the distribution of the weights of these mints is normal with mean 21.37 and variance 0.16.

a) Find the probability that the weight of a single mint selected at random from the production line is less than 20.857 grams.

Standard Deviation = √variance

= √0.16 = 0.4

Standard deviation = 0.4

Mean = 21.37

x = 20.857

z = (x-μ)/σ

z = 20.857 - 21.37/0.4

z = -1.2825

P-value from Z-Table:

P(x<20.857) = 0.099834

b) During a shift, a sample of 100 mints is selected at random and weighed. Approximate the probability that in the selected sample there are at most 5 mints that weigh less than 20.857 grams.

z score formula used = (x-μ)/σ/√n

x = 20.857

Standard deviation = 0.4

Mean = 21.37

n = 100

z = 20.857 - 21.37/0.4/√100

= 20.857 - 21.37/ 0.4/10

= 20.857 - 21.37/ 0.04

= -12.825

P-value from Z-Table:

P(x<20.857) = 0

c) Find the approximate probability that the sample mean of the 100 mints selected is greater than 21.31 and less than 21.39.

5 0
3 years ago
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Ksivusya [100]
Volume=legnth times width times height
convert all to iimporper fractions first for ease
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4 and 1/2=4+1/2=8/2+1/2=9/2

multiply them
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volume=(4 times 13 times 9)/(3 times 8 times 2)
volume=468/48
volume=39/4
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8 0
3 years ago
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