Answer:
a.
Step-by-step explanation:
by elimanation,cimparison or substitution you wull get the value of x=-60/17 and y=6/17
Complete question :
Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.
What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.
Answer:
0.56 ; 0.60
Step-by-step explanation:
From The attached Venn diagram :
C = attend college ; J = has a job
P(C) = (35+45)/300 = 80/300 = 8/30
P(J) = (30+45)/300 = 75/300 = 0.25
P(C n J) = 45 /300 = 0.15
1.)
P(J | C) = P(C n J) / P(C)
P(J | C) = 0.15 / (8/30)
P(J | C) = 0.5625 = 0.56
2.)
P(C | J) = P(C n J) / P(J)
P(C | J) = 0.15 / (0.25)
P(C | J) = 0.6 = 0.60
Answer:
if your going based off of the path that they are taking i say yes because the will meet at the end point or in this case the 1 yard line
Step-by-step explanation:
Correct answer is 4:13 am
Answer:
TBH I would go with either B or D.
Step-by-step explanation:
Well first off your going to 24 miles not 96 or 99 and it doesn't say how much they went on Monday or Tuesday