The data below shows the average number of text messages sent daily by a group of people: 7, 8, 4, 7, 5, 2, 5, 4, 5, 7, 4, 8, 2,
enot [183]
It all depends. You've given us an incredibly vague question.
The outlier could be a number that's low or quite high. Also, outliers
shouldn't really contribute towards the value of the mean, median or
range related to a group of data.
They are called outliers because they are bizarre results or numbers
and should be detached from groups of data. Outliers by definition
are abnormalities or anomalies.
I'd say outliers don't really change anything, unless you actually want
to give them credibility or weight.
Large outliers can inflate the value of means, medians and ranges.
Small outliers will invariably deflate the value of means and medians.
Answer:
smart dot company c=.50t+12
communication plus c=2.50t
Step-by-step explanation:
smart dot has the starting point of $12 per month already so that would be your y-intercept with the equation being y=mx+b , y being the cost m being the amount of money per hour, x being the time spent, and b being the starting cost.
So with that smart dot would be c=.50t+12
with communication plus not having that starting point it would just be c=2.50t
Answer:
<h2><em>
A = 75 in²</em></h2>
Step-by-step explanation:
We have the rectangle and the right triangle.
The formula of an area of a rectangle:
<em>A = lw</em>
<em>l</em> - length
<em>w </em>- width
We have <em>l = 10 in</em> and <em>w = 5 in</em>. Substitute:
<em>A = (10)(5) = 50 in²</em>
The formula of an area of a triangle:
<em>A = 1/2 bh</em>
<em>b</em> - base
<em>h</em> - height
We have <em>b = 5 in</em> and <em>h = 5 in + 5 in = 10 in</em>. Substitute:
<em>A = 1/2(5)(10)=1/2(50)=25 in²</em>
The area of figure:
<h3><em>
A = 50 in² + 25 in² = 75 in²</em></h3>
Answer:
Step-by-step explanation:
52-35=17
17/0.5=34
