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8_murik_8 [283]
3 years ago
14

Write the following parametric equations as a rectangular equation by

Mathematics
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:

3x + y = 12

Step-by-step explanation:

x = 6 - t

y = 3t - 4

We have to convert these equations in rectangular form which means that we have to express them in terms of x and y only. For this we have to eliminate "t".

From first equation we get the value of t as:

x + t = 6

t = 6 - x

Using this value in second equation, we get:

y = 3(6 - x) - 4

y = 18 - 3x - 12

3x + y = 6

This is the equation in rectangular form.

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A rectangle is 12 cm long and 9 cm wide. Its diagonal is labeled 2x - 11. What is the value of x?
shusha [124]

Answer: The value of x is 13 cm.

Explanation:

It is given that the length and width of the rectangle are 12 cm  and 9 cm.

Use pythagoras to find the value of the diagonal.

Hypotenuse=\sqrt{(base)^2+(perpendicular)^2}

D=\sqrt{(12)^2+(9)^2}

D=\sqrt{144+81}

D=\sqrt{225}

D=15

It is given that the diagonal is labeled as 2x-11.

2x-11=15

2x=15+11

2x=26

Divide both side by 2.

x=13

Therefore, x = 13cm.

3 0
3 years ago
Read 2 more answers
Using the quadratic formula to solve 11x2 – 4x = 1, what are the values of x?
sergiy2304 [10]
<h2>Hello!</h2>

The answer is:

x1=0.53\\x2=-0.17

<h2>Why?</h2>

The quadratic formula is:

x=\frac{-b+-\sqrt{b^{2}-4*a*c } }{2*a}

We have that:

a=11\\b=-4\\c=-1

By substituting we have:

x=\frac{4+-\sqrt{-4^{2}-4*11*-1 } }{2*11}=\frac{4+-\sqrt{16+44} }{22}=\frac{4+-\sqrt{60} }{22}=\frac{4+-(7.75)}{22}

x1=\frac{4+7.75}{22}=0.53\\\\x2=\frac{4-7.75}{22} =-0.17

Have a nice day!

7 0
3 years ago
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Answer:

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Step-by-step explanation:

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The hourly salary of five workers are $6, $6, $8, $10, and $35.
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