What is 283 divided it by 5
1 answer:
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Answer:
could not be the same
Step-by-step explanation:
Given that approximately US drivers are agewise as follows:
<25 13.2
25-45 37.7%
>45 49.1%
Observations are made for a sample of 200 fatal accidents.
Let us create hypotheses as
(Two tailed chi square test at 5% significance level)
Age <25 25-45 >45
Expected 13.2 37.7 49.1 100
Observed 42 80 78 200
Expected no 26.4 75.4 98.2 200
Chi square 9.218181818 0.280636605 4.155193483 13.65401191
df = 2
p value = 0.001084
Since p <0.05 we reject null hypothesis
At the 0.05 level, the age distribution of drivers involved in fatal accidents within the state could not be the same as the age distribution of all US drivers as there seems to be significant difference.