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Kruka [31]
3 years ago
7

What number should be placed in the box to help complete the division calculation​

Mathematics
2 answers:
notsponge [240]3 years ago
5 0

Answer:

15

Step-by-step explanation:

12 X 15 is 180, which is closest to 187, we have to add a 5 in the space next to 71 and 180 under 187

DiKsa [7]3 years ago
4 0
The answer is 15 hope it helps
You might be interested in
If m1=2x° and m3=3x° what is m1
olga_2 [115]

Answer:

36

Step-by-step explanation:

Using the angle addition postulate

angle 1+angle 2+angle 3=180

Angle 2 is 90 degrees,

Angle 1 is 2x degrees

Angle 3 is 3x degrees

Plug this into equation

2x + 90 +  3x = 180

5x + 90 = 180

5x = 90

x = 18

Plug 18 into 2x

2(18) = 36

5 0
3 years ago
Who wants to help me out? :)))
Free_Kalibri [48]

Answer:

is that a test or homework

Step-by-step explanation:

I'm a kid so I have no idea

6 0
3 years ago
7 1/2 times 0.50 PLZZZZZ help
Gnom [1K]
3.75  You would multiply 7.5(for 7 1/2) X 0.50=3.75. Hope this helps.
3 0
3 years ago
Read 2 more answers
Solve the given initial-value problem. x' = 1 2 0 1 − 1 2 x, x(0) = 2 7
Ilia_Sergeevich [38]
I'll go out on a limb and guess the system is

\mathbf x'=\begin{bmatrix}\frac12&0\\1&-\frac12\end{bmatrix}\mathbf x

with initial condition \mathbf x(0)=\begin{bmatrix}2&7\end{bmatrix}^\top. The coefficient matrix has eigenvalues \lambda such that

\begin{vmatrix}\frac12-\lambda&0\\1&-\frac12-\lambda\end{vmatrix}=\lambda^2-\dfrac14=0\implies\lambda=\pm\dfrac12

The corresponding eigenvectors \eta are such that

\lambda=\dfrac12\implies\begin{bmatrix}\frac12-\frac12&0\\1&-\frac12-\frac12\end{bmatrix}\eta=\begin{bmatrix}0&0\\1&-1\end{bmatrix}\eta=\begin{bmatrix}0\\0\end{bmatrix}
\implies\eta=\begin{bmatrix}1\\1\end{bmatrix}

\lambda=-\dfrac12\implies\begin{bmatrix}\frac12+\frac12&0\\1&-\frac12+\frac12\end{bmatrix}\eta=\begin{bmatrix}1&0\\1&0\end{bmatrix}\eta=\begin{bmatrix}0\\0\end{bmatrix}
\implies\eta=\begin{bmatrix}0\\1\end{bmatrix}

So the characteristic solution to the ODE system is

\mathbf x(t)=C_1\begin{bmatrix}1\\1\end{bmatrix}e^{t/2}+C_2\begin{bmatrix}0\\1\end{bmatrix}e^{-t/2}

When t=0, we have

\begin{bmatrix}2\\7\end{bmatrix}=C_1\begin{bmatrix}1\\1\end{bmatrix}+C_2\begin{bmatrix}0\\1\end{bmatrix}=\begin{bmatrix}C_1\\C_1+C_2\end{bmatrix}

from which it follows that C_1=2 and C_2=5, making the particular solution to the IVP

\mathbf x(t)=2\begin{bmatrix}1\\1\end{bmatrix}e^{t/2}+5\begin{bmatrix}0\\1\end{bmatrix}e^{-t/2}

\mathbf x(t)=\begin{bmatrix}2e^{t/2}\\2e^{t/2}+5e^{-t/2}\end{bmatrix}
5 0
4 years ago
PLZ HELP WILL GIVE BRAINLEST
Svetradugi [14.3K]

Answer:

The first one (Cedric is correct because he used the inverse of subtraction and added 4.5)

Step-by-step explanation:

First....I'll do it my way

z - 4.5 = -1.5

Add 4.5 on both sides

z - 4.5 + 4.5 = -1.5 + 4.5

z = 3

This should be our answer.....and so who did it right?

Cedric did

Which is the true statement?

Cedric is correct because he used the inverse of subtraction and added 4.5

Hope this helped!

Have a supercalifragilisticexpialidocious day!

8 0
3 years ago
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