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3 years ago

What is 2.8 x 4.6? Find the missing partial products.

1 answer:

4 0

To find each box, you have to multiply the number above the box and the number to the left of the box. For the bottom left, we have 4 x 0.8 or 3.2. For the bottom right, we have 0.8 x 0.6 or 0.48.

hope it helps you friend ☺️

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REY [17]

1. )2.7
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3 years ago

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What is the slope of the line<br><br>

mrs_skeptik [129]

Answer:steepness

Step-by-step explanation:

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3 years ago

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Solve the equation thanks!

AlladinOne [14]

Answer:

c = $\frac{27}{40}$

Step-by-step explanation:

To eliminate the fractions, multiply all terms by the lowest common multiple of 8 and 5

The lowest common multiple of 8 and 5 is 40

5 + 40c = 32 ( subtract 5 from both sides )

40c = 27 ( divide both sides by 40 )

c = $\frac{27}{40}$

8 0

3 years ago

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I need help on answering this question

liubo4ka [24]

Answer:

<h2>The answer is 72°</h2>

Step-by-step explanation:

Since < RQS = < QLK and < RQS = x

< QLK is also x

< QLK and < KLM lie on a straight line

Angles on a straight line add up to 180°

To find x add < QLK and < KLM and equate them to 180°

That's

< QLK + < KLM = 180°

x + x - 36 = 180

2x = 180 - 36

2x = 144

Divide both sides by 2

We have the final answer as

Hope this helps you

7 0

4 years ago

Need help ASAP !!! And show work please

sammy [17]

Answer:

$\sqrt{40}$ or 6.32

Step-by-step explanation:

We can find the distance between two points by using this formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

where the x and y values are derived from the given points

The points given are ( -2 , 5 ) and ( 4 , 3 )

So we plug in the x and y values of those coordinates into the distance formula

$\sqrt{(4-(-2)^2+(3-5)^2} \\4-(-2)=6\\3-5=-2\\d=\sqrt{6^2+-2^2} \\6^2=36\\-2^2=4\\36+4=40\\d=\sqrt{40}$

or 6.32

6 0

3 years ago