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ozzi
3 years ago
7

What is 2.8 x 4.6? Find the missing partial products.

Mathematics
1 answer:
g100num [7]3 years ago
4 0

To find each box, you have to multiply the number above the box and the number to the left of the box. For the bottom left, we have 4 x 0.8 or 3.2. For the bottom right, we have 0.8 x 0.6 or 0.48.

hope it helps you friend ☺️

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8:54 a.m.
dimaraw [331]
Hello,

The two lights flash at the same time every 18 min
at 8:00 h=480 min =480+0*36
at 8:36 h=516 min =480+1*36
...
54 is not divisible by 36
60+12=72 = 2*36 yes
60+24=84 not
120+24=4*36 yes
180+18=198 not

So 2 times are correct 9:12 and 10:24
Answer G


 

5 0
3 years ago
(2.2.5) In horse racing, one can make a trifecta bet by specifying which horse will come in first, which will come in second, an
DaniilM [7]

Answer:

56 ways.

Step-by-step explanation:

This question is solved by using combinations and permutations chapters in the math book.

To put it simply, we need to find the number of 3 horse combinations we can make from 8 horses. This requires the combinations formula:

C(n,r)=\frac{n!}{r!(n-r)!}

here n is the total number of objects to choose from, and r is the number of objects we require in the combination or group.

Since there are 8 horses, n= 8

Since we need to choose only 3 of them, and order does not matter, r= 3

Solving the equation above using these inputs gives us 56 unique ways we can choose the three winners.

7 0
3 years ago
Given these what is X if B-X=A
ser-zykov [4K]

Answer:

B

Step-by-step explanation:

B-X=A

or

B-A=X

or

X=B-A

X=\left[\begin{array}{ccc}-5&-1&6\\4&1&2\\0&-3&2\end{array}\right] -\left[\begin{array}{ccc}-1&-2&3\\4&8&-6\\0&1&5\end{array}\right] \\=\left[\begin{array}{ccc}-5+1&-1+2&6-3\\4-4&1-8&2+6\\0-0&-3-1&2-5\end{array}\right] \\=\left[\begin{array}{ccc}-4&1&3\\0&-7&8\\0&-4&-3\end{array}\right]

3 0
4 years ago
An amount of R351 is made up with 114 coins (R2 coins and R5 coins only). How many R2 coins are there? How many R5 coin are ther
lisabon 2012 [21]

Answer:

41

Step-by-step explanation:

For this, you have to make two equations;

One that calculates the amount of coins

and one that calculates the amount of R

I'm going to set

R2 = x

R5 = y

To make this a bit easier to look at

So to do the number of coins, you want to do this:

x + y = 114

This is saying that the total amount of R2 coins plus the total amount of R5 coins will add up to 114

Then, you want to calculate the worth of them.

2(x) + 5(y) = 351

This is saying that for ever R2 coin there is, it will increase the total by 2, and every R5, it will increase the total by 5. When you add these together, it will come out to 351.

Then you have to solve the system of equations:

x + y = 114

2x + 5y = 351

-2 * (x + y = 114)

2x + 5y = 351

-2x + -2y = -228

2x + 5y = 351

3y = 123

y = 41

Since y is the amount of R5 coins, we know we have 41 R5 coins.

So the answer is

41

4 0
3 years ago
Find the slope between points (-4,0) and (-1,2)
s344n2d4d5 [400]
I got -6, I hope this helps
6 0
4 years ago
Read 2 more answers
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