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3 years ago

Solve two step equations with fractions

Mathematics

1 answer:

MrRa [10]3 years ago

6 0

Whatever you do to one side you do to he other

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Simplify the expression. (16y54y3)12 Enter your answer in the box.

sp2606 [1]

Answer:

Simplify the expression: $(16y^{\frac{5}{4}}y^3)^{\frac{1}{2}}$

Use the exponent power:

$a^n \cdot a^m = a^{n+m}$

$\sqrt[n]{a^n} =a$
$(a^n)^m = a^{nm}$

$(16y^{\frac{5}{4}}y^3)^{\frac{1}{2}}$

Apply the given rules;

$(16y^{\frac{5}{4} +3} )^{\frac{1}{2}}$

Simplify:

$(16y^{\frac{17}{4}} )^{\frac{1}{2}}$

then;

$(16)^{\frac{1}{2}} \cdot (y^{\frac{17}{4}})^{\frac{1}{2}} = 4y^{\frac{17}{8}}$

Therefore, the simplified expression of $(16y^{\frac{5}{4}}y^3)^{\frac{1}{2}}$ is, $4y^{\frac{17}{8}}$

7 0

2 years ago

5 (3z-3) =30 it’s from delta math 8 grade

Mkey [24]

Answer:

$5$

Step-by-step explanation:

Substitute the value of the variable into the equation and simplify.

3 0

2 years ago

Read 2 more answers

What is the perimeter of parallelogram HIJK? Round to the nearest hundredth.

bixtya [17]

Answer:

Perimeter of the parallelogram = 26.64 units

Step-by-step explanation:

The perimeter of parallelogram = 2(a + b)

Here a = KJ = 7 units.

b = HK

We need to find the HK using the distance formula.

Distance formula = $\sqrt{(x2 - x1)^2 + (y2 - y1)^2}$

H = (-4, 3) and k = (-2, -3)

Now plug in x1 = -4, y1 =3, x2 = -2, y2 = -3 in the distance formula

HK = $\sqrt{(-2 -(-4))^2 + (-3 - 3)^2}$

= $\sqrt{(-2 +4)^2 + (-6)^2}$

= $\sqrt{4 + 36}$

= $\sqrt{40}$

HK = b = 6.32 units

Now plug in a = 7 and b = 6.32 in the perimeter formula, we get

Perimeter = 2(7 + 6.32)

= 2(13.32)

= 26.64 units

Thank you.

6 0

2 years ago

Factor the expression: -x - 6 =

tia_tia [17]

Answer:

- ( x + 6) I think

7 0

2 years ago

Read 2 more answers

Write the quadratic function in standard form.<br> f(x) = -x2 + 2x + 4<br> f(x) =

goldenfox [79]

Answer:

$f(x)=-1(x-2)^2+8$

Step-by-step explanation:

Given:

The quadratic function is given as:

$f(x)=-x^2+2x+4$

The standard form of a quadratic function is given as:

$f(x)=a(x-h)^2+k$ , where, 'a', 'h' and 'k' are real numbers.

Now, in order to convert the given function to standard form, we use completing by square method.

$-x^2+2x=-(x^2-2x)=-[(x-2)^2-2^2]=-[(x-2)^2-4]=-(x-2)^2+4$

Now, $f(x)=-x^2+2x+4$ can be rewritten as:

$f(x)=-(x-2)^2+4+4\\f(x)=-1(x-2)^2+8$

Therefore, the standard form of the function is:

$f(x)=-1(x-2)^2+8$

7 0

2 years ago