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3 years ago

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The opening in a rectangular door frame measures 9 feet by 3 feet. Each of the four doors described in the table measures 9 feet

by 3 feet, but have different diagonal lengths. Which door will fit in the rectangular opening? Door 1 diagonal: 10 feet Door 2 diagonal: 3 StartRoot 10 EndRoot feet Door 3 diagonal: 6 StartRoot 2 EndRoot feet Door 4 diagonal: 12 feet Door 1 Door 2 Door 3 Door 4

2 answers:

love history [14]3 years ago

6 0

Answer:

the answer is 2

i took the quiz

Scilla [17]3 years ago

3 0

Answer: 2

Step-by-step explanation:

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The zeros of a parabola are -5 and -3. The point (0, 60) is on the graph as represented by the equation.

ra1l [238]

Answer:

a=4

Step-by-step explanation:

60=a(0+5)(0+3)

We can simplify this equation

60 = a (5) (3)

60 = a(15)

Divide each side by 15

60/15 = 15a/15

4 =a

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3 years ago

Read 2 more answers

Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of the survey asked respondents to

erastova [34]

Answer:

(a) The probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.

(b) The probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.

Step-by-step explanation:

Let's denote the events as follows:

<em>A</em> = Fell short of expectations

<em>B</em> = Met expectations

<em>C</em> = Surpassed expectations

<em>N</em> = no response

<u>Given:</u>

P (N) = 0.04

P (A) = 0.26

P (B) = 0.65

(a)

Compute the probability that a randomly selected alumnus would say their experience surpassed expectations as follows:

$P(C) = 1 - [P(A) + P(B) + P(N)]\\= 1 - [0.26 + 0.65 + 0.04]\\= 1 - 0.95\\= 0.05$

Thus, the probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.

(b)

The response of all individuals are independent.

Compute the probability that a randomly selected alumnus would say their experience met or surpassed expectations as follows:

$P(B\cup C) = P(B)+P(C)-P(B\cap C)\\=P(B)+P(C)-P(B)\times P(C)\\= 0.65 + 0.05 - (0.65\times0.05)\\=0.6675\\\approx0.67$

Thus, the probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.

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4 years ago

3(x+4)-15=15 , 3x+12-15=10 what property is that?

Anika [276]

Answer: this is distributive property

Step-by-step explanation:

You multiplied inside the parenthesis

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3 years ago

Asap asnwerrrrrrrrrrrrrrrrrrrrrrrr

Mashcka [7]

Angle 3 is 96 degrees - angles on a straight line add up to 180 degrees

Hope this helps!

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3 years ago

From the sum of a2−2ab+b2 and 2a2+2ab+b2 subtract the sum of a2−b2 and a2+ab+3b2

Sedaia [141]

Answer:

$a^2-ab$

Step-by-step explanation:

We need to find the sum of $a^2-2ab+b^2$ and $2a^2+2ab+b^2$ first.

Adding $a^2-2ab+b^2$ + $2a^2+2ab+b^2$

Combining like terms, we get

$a^2+2a^2=3a^2$

-2ab+2ab = 0

$b^2+b^2=2b^2$

Therefore,

$a^2-2ab+b^2 +2a^2+2ab+b^2=3a^2+2b^2$ .

Now, we need to find the sum of $a^2-b^2 \ \ and \ \ a^2+ab+3b^2.$ .

Adding $a^2−b^2+a^2+ab+3b^2$ .

Combining like terms, we get

$a^2+a^2=2a^2$

$-b^2+3b^2=2b^2$ .

Therefore,

$a^2−b^2+a^2+ab+3b^2=2a^2+ab+2b^2.$

Now, subtracting

$3a^2+2b^2 -(2a^2+ab+2b^2)$ .

Distributing minus sign over second parenthesis, we get

$3a^2+2b^2-2a^2-ab-2b^2$ .

Combining like terms,

$3a^2-2a^2=a^2$

$2b^2-2b^2=0$

Therefore,

$3a^2+2b^2-2a^2-ab-2b^2=a^2-ab$ .

Therefore, the difference of the sum of $a^2-2ab+b^2$ + $2a^2+2ab+b^2$ and $a^2-b^2+a^2+ab+3b^2.$ is $a^2-ab.$

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3 years ago