Answer:
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Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer:
F = $11,421.90
Final value after 5 years F = $11,421.90
Complete question;
You purchased a vehicle for $32,000. It's value will depreciate at a rate of 18.62%. What will it's value be in 5 years, when you finally have it paid off
Step-by-step explanation:
Given;
Initial value P = $32,000
Depreciation rate r = 18.62% = 0.1862
Time t = 5
Final value = F
Using the compound depreciation formula;
F = P(1 - r)^t
Substituting the values;
F = $32,000(1 - 0.1862)^5
F = $11,421.90
Final value F = $11,421.90
The rate of the cups of vinegar per tablespoon of lemon oil is two per tablespoon rates in cups
Answer:
21
Step-by-step explanation:
