We have
2x+3y=5
Step 1
find two points of the line
for x=0--------------> y=5/3 point (0,1.67)
for y=0 --------------> x=5/2 point (2.5,0)
The vector between two points is v =(2.5-0,0-1.67)=(2.5.-1.67)
Vector form: r=ro+tv----------> (2.5,0)+(2.5,-1.67)t
Parametric form
x=2.5+2.5t
y=-1.67t
the answer is
x=2.5+2.5t
y=-1.67t
Answer:
10y + 29 ≤ -23
Step-by-step explanation:
subtract 29 from each side to get:
10y ≤ -52
y ≤ -5.2
7x3=21 idk if that helps any
X-7 - -2x-5
answer is 2/3
X-7 + 2X= -2x-5+2x
3x-7= -5
3x-7+7= -5+7 (getting x alone)
3x=2
divide by 3 to get x
3x/3 =2/3
x=2/3