Answer:
I think 4000 worker and I will be there at some point today and I
I am assuming you're doing a Punnet square, so you multiply each one. So on the top left box, it is -45x^2, the top right is 9x, bottom left is 35x, and bottom right is -7.
Answer:
x = 4y + 5
Step-by-step explanation:
x represents the total students in the class. We don't know how many teams of four there will be, so we represent that with y. 4y represents the total students in teams of 4. We know there is one team of 5, so that is added to 4y.
This is a linear equation with y-intercept $50 and slope $0.25/mile:
TC = $50 + ($0.25)x, where x is the number of miles driven.
Answer:
Cos A=5/13
we have
Cos² A=
25/169=1-Sin²A
sin²A=1-25/169
sin²A=144/169
Sin A=
again
Tan B=4/3
P/b=4/3
p=4
b=3
h=
Now
Sin B=p/h=4/5
in IV quadrant sin angle is negative so
Sin B=-4/5
CosB=b/h=3/5
Now
<u>S</u><u>i</u><u>n</u><u>(</u><u>A</u><u>+</u><u>B</u><u>)</u><u>:</u><u>s</u><u>i</u><u>n</u><u>A</u><u>c</u><u>o</u><u>s</u><u>B</u><u>+</u><u>C</u><u>o</u><u>s</u><u>A</u><u>s</u><u>i</u><u>n</u><u>B</u>
<u>n</u><u>o</u><u>w</u><u> </u>
<u>substitute</u><u> </u><u>value</u>
<u>Sin(A+B):</u>12/13*3/5+5/13*(-4/5)=36/65-4/13
<u>=</u><u>1</u><u>6</u><u>/</u><u>6</u><u>5</u><u> </u><u>i</u><u>s</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u>