All categories

3 years ago

Myra will attend college in 18 months.

Mathematics

2 answers:

koban [17]3 years ago

8 0

6,300 - 2,400 -1,900 = 2,000. 2,000 divided by 18 is $111.11. So the answer is B

otez555 [7]3 years ago

4 0

Answer:

A. 2,000.00

Step-by-step explanation: If she already has $2,400 and $1,900 which equals $4,300 she will only need $2,000 more dollars

2,400+1,900=4,300+2,000=6300

You might be interested in

Carlie is painting a trunk that measures 40 inches wide, 30 inches tall, and 60 inches long. Which is the correct unit of measur

HACTEHA [7]

Answer:

in2 because it is surface area

Step-by-step explanation:

6 0

4 years ago

Find the slope (6, -2) (2, -6)

Harlamova29_29 [7]

Answer:

-1/3

Step-by-step explanation:

I hope this helps!

5 0

3 years ago

Read 2 more answers

One central idea in the Declaration of Independence is that Americans should get rid of the British government and form a new on

AleksAgata [21]

Answer:

number 1

Step-by-step explanation:

8 0

3 years ago

Find the mass of the solid paraboloid Dequals={(r,thetaθ,z): 0less than or equals≤zless than or equals≤8181minus−r2, 0less th

Lubov Fominskaja [6]

Answer:

M = 5742π

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

ρ ( r, θ , z ) = 1 + z / 81

- The solid is bounded by the planes:

0 ≤ z ≤ 81 - r^2

0 ≤ r ≤ 9

Find:-

Find the mass of the solid paraboloid

Solution:-

- The mass (M) of any solid body is given by the following triple integral formulation:

$M = \int \int \int {p ( r ,theta, z)} \, dV\\\\$

- We can write the above expression in cylindrical coordinates:

$M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\$

- Perform integration:

$M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\$

$M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] } \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] } \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] } \, dtheta\\\\M = 5742\pi kg$

- The mass evaluated is M = 5742π

8 0

3 years ago

The question is in the screenshot.

Musya8 [376]

Answer:

v = 4

Step-by-step explanation:

a (-2) multiplied by t (3) = -6

-6 + u (10) = 4

5 0

3 years ago

Read 2 more answers